Python：制作多个bash脚本的脚本 [英] Python: script to make multiple bash scripts

问题描述

$ b

  input1.txt $ 
 
我有一个名为list.txt的文件，它是一个文件名列表。 b $ b input2.txt 
 input3.txt 
  

我想构建一个python脚本将为每个这些文件名创建一个文件。更确切地说，我需要它来打印一些文本，合并文件的名称，并将其保存到一个独特的.sh文件。我的脚本如下：

  import os 
 os.chdir（/ Users / user / Desktop / Folder ）
 
打开（'list2.txt'，'r'）为f：
 lines = f.read（）。split（''）
 
对于l行：
 print＃！/ bin / bash\\\
＃BSUB -J，l +。sh，\\\
＃BSUB -o / scratch / DBC / user /+ l + .sh.out \\\
＃BSUB -e /scratch/DBC/user/\"+l+\".sh.err\\\
#BSUB -n 1 \\\
＃BSUB -q normal\\\
＃BSUB -P DBCDOBZAK\\\
＃BSUB -W 168：00\\\

 printcd / scratch / DBC / user\\\

打印grep输入'，l +>结果。 （l），'w'）作为输出：
 output.write（l）$ b+ l +.txt
 
 with open $ b  

我有几个问题：

• 输出文件只包含文件的名称 - 不是我打印的内容。

输出文件（我应该有3个）应该看起来像这样：
$ b $ pre $ $ bin
$＃ Ĵ input3.sh
#BSUB -o /scratch/DBC/user/input1.sh.out
#BSUB -e /scratch/DBC/user/input3.sh.err
#BSUB - n 1
#BSUB -q正常
#BSUB -P DBCDOBZAK
#BSUB -W 168：00

cd / scratch / DBC / user
grepinputinput3> result.input3.txt

我对Python非常陌生，所以我认为可以有更简单的方法打印和插入我的文字。任何帮助将不胜感激。

更新
我现在已经做了下面的脚本，几乎可以工作。

$ b $

  import os 
 os.chdir（/ Users / user / Desktop / Folder）
 
 with打开（'list.txt'，'r'）为f：
 lines = f.read（）。split（'\\\
'）
 
 $ b header =＃！/ bin / bash \\\
＃BSUB -J％s.sh \\\
＃BSUB -o /scratch/DBC/user/%s.sh.out \\\
＃BSUB -e / scratch / DBC / user /％s.sh.err \\\
＃BSUB -n 1 \\\
＃BSUB -q normal \\\
＃BSUB -P DBCDOBZAK \\\
＃BSUB -W 168：00\\\
 ％（l，l，l）
 script =cd / scratch / DBC / user\\\

 script2 ='grep'input'％s>结果。％s.txt\\\
'％（l，l）
 all =\\\
.join（[header，script，script2]）
 
 with open（'脚本_ {}。sh'.format（l），'w'）作为输出：
 output.write（全部）
  

我仍然有这个问题，它会创建4个脚本，而不是像我预期的那样创建3个脚本：script_input1.sh，script_input2.sh，script_input3.sh和script_sh。最后一个，script_sh只是打印文本，但没有任何输入文本的地方。我认为这是因为我的list.txt文件有一个\ n在它的结尾？但是，我看了，真的没有。有没有解决的办法？也许我可以使用某种长度的函数？
解决方案

另一个解决方案，而不是创建文件

  script1.sh 
 script2.sh 
 script3.sh 
  

等。将创建一个文件文件 script.sh

 ＃！/ bin / bash 
 #BSUB -J$ 1.sh 
 #BSUB -o /scratch/DBC/user/\"$1\".sh.out 
 #BSUB -e / scratch / DBC /user/\"$1\".sh.err 
 #BSUB -n 1 
 #BSUB -q正常
 #BSUB -P DBCDOBZAK 
 #BSUB -W 168：00 
 
 cd / scratch / DBC / user 
 grepinput$ 1>结果$ 1.txt 
  

使用

  script.sh input1 
 script.sh input2 
 script.sh input3 
  

I have a file, called list.txt, which is a list of names of files:

input1.txt
input2.txt
input3.txt

I want to build a python script that will make one file for each of these filenames. More precisely, I need it to print some text, incorporate the name of the file and save it to a unique .sh file. My script is as follows:

import os
os.chdir("/Users/user/Desktop/Folder")

with open('list2.txt','r') as f:    
    lines = f.read().split(' ')

for l in lines:
    print "#!/bin/bash\n#BSUB -J",l+".sh","\n#BSUB -o /scratch/DBC/user/"+l+".sh.out\n#BSUB -e /scratch/DBC/user/"+l+".sh.err\n#BSUB -n 1\n#BSUB -q normal\n#BSUB -P DBCDOBZAK\n#BSUB -W 168:00\n"
    print "cd /scratch/DBC/user\n"
    print 'grep "input"',l+" > result."+l+".txt"

    with open('script{}.sh'.format(l), 'w') as output:
        output.write(l)

I have a few issues:

• The output files just contain the name of the file - not the content I have printed.

To be clear my output files (I should have 3) should look like this:

#!/bin/bash
#BSUB -J input3.sh 
#BSUB -o /scratch/DBC/user/input1.sh.out
#BSUB -e /scratch/DBC/user/input3.sh.err
#BSUB -n 1
#BSUB -q normal
#BSUB -P DBCDOBZAK
#BSUB -W 168:00

cd /scratch/DBC/user
grep "input" input3 > result.input3.txt

I am very new to Python so I am assuming there could be much simpler ways of printing and inserting my text. Any help would be much appreciated.

UPDATE I have now made the following script, which nearly works.

import os
os.chdir("/Users/user/Desktop/Folder")

with open('list.txt','r') as f:
    lines = f.read().split('\n')

for l in lines:
    header = "#!/bin/bash \n#BSUB -J %s.sh \n#BSUB -o /scratch/DBC/user/%s.sh.out \n#BSUB -e /scratch/DBC/user/%s.sh.err \n#BSUB -n 1 \n#BSUB -q normal \n#BSUB -P DBCDOBZAK \n#BSUB -W 168:00\n"%(l,l,l)
    script = "cd /scratch/DBC/user\n"
    script2 = 'grep "input" %s > result.%s.txt\n'%(l,l)
    all= "\n".join([header,script,script2])

    with open('script_{}.sh'.format(l), 'w') as output:
        output.write(all)

The problem I still have is that this creates 4 scripts, not 3 as I expected: script_input1.sh, script_input2.sh, script_input3.sh and script_sh. This last one, script_sh just has the printed text but nothing where the "input" text would be. I think this is because my list.txt file has a "\n" at the end of it? However, I looked and there really isn't. Is there a way around this? Maybe I can use some kind of length function?

解决方案

Another solution that, instead of creating files

script1.sh
script2.sh
script3.sh

etc. would be to create one file file script.sh

#!/bin/bash
#BSUB -J "$1".sh 
#BSUB -o /scratch/DBC/user/"$1".sh.out
#BSUB -e /scratch/DBC/user/"$1".sh.err
#BSUB -n 1
#BSUB -q normal
#BSUB -P DBCDOBZAK
#BSUB -W 168:00

cd /scratch/DBC/user
grep "input" "$1" > result."$1".txt

and run it using

script.sh input1
script.sh input2
script.sh input3

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