括号中的四个“东西”的for循环是如何工作的？ [英] How does a for-loop with four 'things' in the parenthesis work i Javascript?

问题描述

我在这里遇到了一些代码 https://stackoverflow.com/a/2922778/2176900 ，这对于（i = 0，j = nvert-1; i< nvert; j = i ++）{... b
$ b

  。
  

我不明白它在括号内有四件事情时会做什么（ i = 0，j = nvert-1，i $ b

谢谢

解决方案

它没有四件事;它仍然有三个。

• 预循环语句
  
  i = 0，j = nvert-1




• 迭代条件 <
  i <




• 迭代后操作
  
  j = i ++

预循环语句实际上应该是：

var i = 0，j = nvert-1

记住我们可以声明多个变量在一个单一的声明。这就是发生在这里的事情。

I came across some code here https://stackoverflow.com/a/2922778/2176900 that started off like this:

for (i = 0, j = nvert-1; i < nvert; j = i++) {...`

and I don't understand what it does when it has four things within the parenthesis ("i = 0", "j = nvert-1", "i < nvert" and "j = i++"). I've obviously been trying to google this, but can't seem to find any answers. I'm sure if I just knew what the things in the parenthesis was called I'd be glad.

Thanks

解决方案

It doesn't have four things; it still has three.

• The pre-loop statement
  i = 0, j = nvert-1

• The iteration condition
  i < nvert

• The post-iteration action
  j = i++

That pre-loop statement is actually probably supposed to read:
var i = 0, j = nvert-1

Remember that we can declare multiple variables in a single declaration. That's what's happening here.

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