在我的ExpandableListView适配器中重复 [英] Duplicates in my ExpandableListView Adapter

问题描述

问题是，每当我在ExpandableListView中向一个GroupItem中添加多个Child时，该项目都与前一个子项重复。我已经缩小到我的ExpandableListView（自定义）适配器中的getChild（）方法。

getChild（）方法如下所示：

  public Object getChild（int groupPosition，int childPosition）{
 
 return rCollection.get（weekData.get（groupPosition））。get （childPosition）; 
 
 $ b  

其中 rCollection = Map< String ，< Custom>> ;;
和 weekData = List< String> ;

我如何更改getChild每个请求只返回一个项目，所以我不重复？我不能使用for循环，因为如果我将groupPosition和childPosition更改为数组，我将不得不再次实现该方法。为了说明，这是问题例如：

第一次被调用时，我如何排除项目2的被拾取，以及如何在第二次调用项目1时不被调用？等等。

感谢您的阅读和所有帮助。 解决方案

  @Override 
 public int getChildCount（.....）
 {
 return 2; 
 
 
 
 $ b $ p 
 $ b 
如果您确定每个项目只有2个子项目
 
 
对不起，这是你想要的正确方法。 
 
 编辑 
  
 
 
  @Override 
 public int getChildrenCount（int groupPosition）
 {
 return（rCollection.get（weekdata.get（groupPosition（）））。size（）; 
} 
  
这将返回您的列表< Custom> 的大小（长度） 
 
如果需要的话，
 均衡paranthesis   
the problem goes is that everytime I add more than one Child to a GroupItem in my ExpandableListView, the item duplicates itself with the previous child. I have narrowed it down to the  getChild() method in my ExpandableListView (custom) adapter.


The getChild() method looks like this: 
public Object getChild(int groupPosition, int childPosition) {

     return rCollection.get(weekData.get(groupPosition)).get(childPosition);

}
Where rCollection = Map<String, List<Custom>>;
and weekData = List<String>;

How do I change the getChild to return only one item per request so I dont get duplicates? I cannot use a for-loop because if I change the groupPosition and childPosition to Arrays I will have to implement the method again.

To Illustrate, this is what the issue looks like:



How do I exclude the Item 2 from being picked up by the first time it is called, and how do I exclude item 1 from being called the second time it is called? And so on.

Thank you for reading and all the help.
解决方案
@Override
public int getChildCount(.....)
{
     return 2;
}
If you are sure that for every item there are only 2 subitems 

Sorry my bad this is the right method you want. 

 EDIT 
@Override
public int getChildrenCount(int groupPosition)
{
    return (rCollection.get(weekdata.get(groupPosition())).size();
}
This will return the size (length) of your List<Custom> for a map. 

balance paranthesis if needed

                        
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