解决循环 [英] Working around for loop

问题描述

我已经注意到类似的重复，并试图解决这个问题，如果我可以尽量减少代码长度：

我不需要使用开关的情况下，如果我可以形成一个循环，而不是？

1. $ returnNo变量从5开始，每个case乘以2 then
   

2. 它显示$ a< =，它从5开始，每个大小写乘以2再加上3。

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3. 从if（$ matchno == 7）开始的if（）语句，每个case乘以2再加上1。

到64的情况下，实际上会达到512.据我所知，代码重复我希望有人可以帮助我产生一个单一的循环吗？




非常感谢！


 开关（$ max）{
 
案例80：
 $ returnNO = 5; （$ a = 1; $ a< = 5; $ a ++）{
 if（$ matchno == $ a || $ matchno ==（$ a + 1））{$ b $ 
 b $ matchinfo ['matchno'] = $ returnNO; 
 $ matchinfo ['place'] =（$ matchno == $ a？'clan1'：'clan2'）; 
返回$ matchinfo; 
} 
 $ returnNO ++; 
 $ a ++; 
 
 if（$ matchno == 7）{
 $ matchinfo ['winner'] = true; 
返回$ matchinfo; 
} elseif（$ matchno == 8）{
 $ matchinfo ['third_winner'] = true; 
返回$ matchinfo; 
} 
 break; 
 
案例160：
 $ returnNO = 9; （$ a = 1; $ a< = 13; $ a ++）{
 if（$ matchno == $ a || $ matchno ==（$ a + 1））{
 $ matchinfo ['matchno'] = $ returnNO; 
 $ matchinfo ['place'] =（$ matchno == $ a？'clan1'：'clan2'）; 
返回$ matchinfo; 
} 
 $ returnNO ++; 
 $ a ++; 
 
 if（$ matchno == 15）{
 $ matchinfo ['winner'] = true; 
返回$ matchinfo; 
} elseif（$ matchno == 16）{
 $ matchinfo ['third_winner'] = true; 
返回$ matchinfo; 
} 
 break; 
 
案例320：
 $ returnNO = 17; （$ a = 1; $ a< = 29; $ a ++）{
 if（$ matchno == $ a || $ matchno ==（$ a + 1））{
 $ matchinfo ['matchno'] = $ returnNO; 
 $ matchinfo ['place'] =（$ matchno == $ a？'clan1'：'clan2'）; 
返回$ matchinfo; 
} 
 $ returnNO ++; 
 $ a ++; 
} 
 
 if（$ matchno == 31）{
 $ matchinfo ['winner'] = true; 
返回$ matchinfo; 
} elseif（$ matchno == 32）{
 $ matchinfo ['third_winner'] = true; 
返回$ matchinfo; 
} 
 break; 
 case 640：
 $ returnNO = 33; （$ a = 1; $ a< = 61; $ a ++）{
 if（$ matchno == $ a || $ matchno ==（$ a + 1））{$ b $ 
 b $ matchinfo ['matchno'] = $ returnNO; 
 $ matchinfo ['place'] =（$ matchno == $ a？'clan1'：'clan2'）; 
返回$ matchinfo; 
} 
 $ returnNO ++; 
 $ a ++; 
 
 if（$ matchno == 63）{
 $ matchinfo ['winner'] = true; 
返回$ matchinfo; 
} elseif（$ matchno == 64）{
 $ matchinfo ['third_winner'] = true; 
返回$ matchinfo; 
} 
 break; 
 
 
 $ b $ / code $ / $ p 
 
解决方案
 
  switch（$ max）{
 case 80：
 $ returnNO = 5; 
 $ loopCount = 5; 
 $赢家= 7; 
 $ thirdWinner = 8; 
 break; 
 
案例160：
 $ returnNO = 9; 
 $ loopCount = 13; 
 $赢家= 15; 
 $ thirdWinner = 16; 
 break; 
 
 
 $ b $（$ a = 1; $ a< = $ loopCount; $ a ++）{
 if（$ matchno == $ a || $ matchno ==（$ a + 1））{
 $ matchinfo ['matchno'] = $ returnNO; 
 $ matchinfo ['place'] =（$ matchno == $ a？'clan1'：'clan2'）; 
返回$ matchinfo; 
 
 
 $ b $ if（$ matchno == $ winner）{
 $ matchinfo ['winner'] = true; 
返回$ matchinfo; 
} else if（$ matchno == $ thirdWinner）{
 $ matchinfo ['third_winner'] = true; 
返回$ matchinfo; 
 
 
 
 
 
 $ b简单地解释一下，删除一直重复的代码并尝试对它进行参数化（通过创建一个函数或者把所有重复的代码放在其他地方...在这个例子中，我把重复的代码放在switch语句之后，并且将其重新计算。
I have noticed similar repetition and trying to work around using a single for loop for this if I can to minimize the code length:

I wouldn't need to use a switch case if I can form a loop instead?

$returnNo variable starts at 5, each case multiplied by 2 then minus 1.
where it shows "$a<=", it starts at 5 and each case multiplied by 2 then plus 3.
the if() statement starting at if($matchno == 7), each case multiplied by 2 then plus 1.
the final if() statement starting at if($matchno == 8), each case multiplied by 2.
I have done up to case 64, it will actually go up to 512. As I know the code is repeating I am hoping someone can help me produce a single loop for this?
Many thanks!
    switch($max) {

    case 80 :
        $returnNO = 5;
        for($a = 1; $a<=5; $a++) {
            if($matchno == $a || $matchno == ($a+1)){
                $matchinfo['matchno'] = $returnNO;
                $matchinfo['place'] = ($matchno == $a ? 'clan1' : 'clan2');
                return $matchinfo;
            }
            $returnNO++;
            $a++;
        }
        if($matchno == 7){
            $matchinfo['winner'] = true;
            return $matchinfo;
        }elseif($matchno == 8){
            $matchinfo['third_winner'] = true;
            return $matchinfo;
        }
    break;

    case 160 :
        $returnNO = 9;
        for($a = 1; $a<=13; $a++) {
            if($matchno == $a || $matchno == ($a+1)){
                $matchinfo['matchno'] = $returnNO;
                $matchinfo['place'] = ($matchno == $a ? 'clan1' : 'clan2');
                return $matchinfo;
            }
            $returnNO++;
            $a++;
        }
        if($matchno == 15){
            $matchinfo['winner'] = true;
            return $matchinfo;
        }elseif($matchno == 16){ 
            $matchinfo['third_winner'] = true;
            return $matchinfo;
        }
    break;

    case 320 :
        $returnNO = 17;
        for($a = 1; $a<=29; $a++) {
            if($matchno == $a || $matchno == ($a+1)){
                $matchinfo['matchno'] = $returnNO;
                $matchinfo['place'] = ($matchno == $a ? 'clan1' : 'clan2');
                return $matchinfo;
            }
            $returnNO++;
            $a++;
        }

        if($matchno == 31){
            $matchinfo['winner'] = true;
            return $matchinfo;
        } elseif($matchno == 32){
            $matchinfo['third_winner'] = true;
            return $matchinfo;
        }
    break;
    case 640 :              
        $returnNO = 33;
        for($a = 1; $a<=61; $a++) {
            if($matchno == $a || $matchno == ($a+1)){
                $matchinfo['matchno'] = $returnNO;
                $matchinfo['place'] = ($matchno == $a ? 'clan1' : 'clan2');
                return $matchinfo;
            }
            $returnNO++;
            $a++;
        }   
        if($matchno == 63){
            $matchinfo['winner'] = true;
            return $matchinfo;
        }elseif($matchno == 64){
            $matchinfo['third_winner'] = true;
            return $matchinfo;
        }               
    break;      

    }
}

解决方案
I'll use the first two cases as an example:
switch ($max) {
case 80:
        $returnNO = 5;
        $loopCount = 5;
        $winner = 7;
        $thirdWinner = 8;
        break;

    case 160:
        $returnNO = 9;
        $loopCount = 13;
        $winner = 15;
        $thirdWinner = 16;
        break;
    ...
}

for ($a = 1; $a <= $loopCount; $a++) {
    if ($matchno == $a || $matchno == ($a + 1)) {
        $matchinfo['matchno'] = $returnNO;
        $matchinfo['place'] = ($matchno == $a ? 'clan1' : 'clan2');
        return $matchinfo;
    }
}

if ($matchno == $winner) {
    $matchinfo['winner'] = true;
    return $matchinfo;
} else if ($matchno == $thirdWinner) {
    $matchinfo['third_winner'] = true;
    return $matchinfo;
}
Simply explained, remove the code that repeats all the time and try to parameterize it (either by creating a function or by putting all repeated code somewhere else... in this example, I put the repeating code after the switch statement and paremeterized it.

                        
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