将NSString转换为For循环内的字符数组 [英] Converting NSString to array of chars inside For Loop

问题描述

我尝试使用iOS项目中的现有代码来将数组中的单词列表（例如，使番茄变成毫无用处，或者堆积成一堆）。代码似乎工作，如果我自己运行它，但我试图将其集成到我现有的应用程序。

每个字我希望它alphabetize存储作为一个数组内的NSString。这个问题似乎是代码把这个词作为一个字符数组，我不能让我的NSString成为这种格式。

如果我使用 string = [currentWord UTFString] ，我得到错误数组类型char [128]不可分配，如果我尝试在循环中创建字符数组（ const char * string = [curentWord UTF8String] ）我得到与有关的警告类型为const的char初始化char抛出限定符。不太清楚我可以绕过它 - 任何提示？下面的方法，我会照顾存储的alphabetized版本以后。

   - （void）alphabetizeWord {
 char char [128]，temp; 
 int n，i，j; 
 
（NSString * currentWord in wordsList）{
 n = [currentWord length]; （j = i + 1; j  if（string [i]）的
对于（i = 0; i< n-1; > string [j]）{
 temp = string [i]; 
 string [i] = string [j]; 
 string [j] = temp; 
 
 
 $ b NSLog（@单词％@按字母顺序排列是％s，currentWord，string）; 
 
 
 $ / code $ / pre 
 
解决方案
应该工作：
 
 
   - （void）alphabetizeWord {
 char str [128]; 
 $ b $ for（NSString * currentWord in wordList）
 {
 int wordLength = [currentWord length]; 
 for（int i = 0; i  {
 str [i] = [currentWord characterAtIndex：i]; 
} 
 //添加终止字符
 str [wordLength] = 0; 
 // Add your word 
} 
} 
  
编辑：对不起，起初并不完全了解。要检查一下。
 
I'm trying to use an existing piece of code in an iOS project to alphabetize a list of words in an array (for instance, to make tomato into amoott, or stack into ackst). The code seems to work if I run it on its own, but I'm trying to integrate it into my existing app.

Each word I want it to alphabetize is stored as an NSString inside an array. The issue seems to be that the code takes the word as an array of chars, and I can't get my NSStrings into that format.

If I use string = [currentWord UTFString], I get an error of Array type char[128] is not assignable, and if I try to create the char array inside the loop (const char *string = [curentWord UTF8String]) I get warnings relating to Initializing char with type const char discards qualifiers. Not quite sure how I can get around it – any tips? The method is below, I'll take care of storing the alphabetized versions later.
- (void) alphabetizeWord {
    char string[128], temp;
    int n, i, j;

    for (NSString* currentWord in wordsList) {
        n = [currentWord length];
        for (i = 0; i < n-1; i++) {
            for (j = i+1; j < n; j++) {
                if (string[i] > string[j]) {
                    temp = string[i];
                    string[i] = string[j];
                    string[j] = temp;
                }
            }
        }
        NSLog(@"The word %@ in alphabetical order is %s", currentWord, string);
    }
}

解决方案
This should work :
- (void)alphabetizeWord {
  char str[128];

  for (NSString *currentWord in wordList)
  {
    int wordLength = [currentWord length];
    for (int i = 0; i < wordLength; i++)
    {
      str[i] = [currentWord characterAtIndex:i];
    }
    // Adding the termination char
    str[wordLength] = 0;
    // Add your word
  }
}
EDIT : Sorry, didn't fully understand at first. Gonna check this out.

                        
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