Bash脚本循环内存不足? [英] Bash Script Loop Out of Memory?

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本文介绍了Bash脚本循环内存不足?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

在bash中,我需要运行一个从i = 1到i = 99999999循环的脚本,但是它总是耗尽内存。有没有解决办法?或者是有一个最大值为我?

$ pre $ code $ first $ 1 b $ b last $ 99999999
randomString = CXCXQOOPSOIS

for $(seq $ first $ last)
do
padVal = $(printf%010d\\\
$ val)
hash = $(echo -n $ randomString $ padVal | md5sum)
if [[$ hash=〜^ 000000)]];然后
回显Number:$ val>> log_000000
echo$ val添加到日志 - 请检查。
fi
done


解决方案

bash 为循环提供类似C的语法

<$ p $ ((val = $ first; val< $ last; val ++)

last = 99999999
randomString =CXCXQOOPSOIS


do $ b $ padVal = $(printf%010d\\\
$ val)
hash = $(echo -n $ randomString $ padVal | md5sum)
if [ $ hash=〜^ 000000)]];然后
回显Number:$ val>> log_000000
echo$ val添加到日志 - 请检查。
fi
完成


In bash I need to run a script that loops from i=1 to i=99999999 but it always run out of memory. Is there any workaround? or is there a max value for i?

first=1
last=99999999
randomString="CXCXQOOPSOIS"

for val in $( seq $first $last )
do
  padVal=$( printf "%010d\n" $val )
  hash=$( echo -n $randomString$padVal | md5sum )
  if [[ "$hash" =~ ^000000) ]]; then
    echo "Number: $val"  >> log_000000
    echo "$val added to log - please check."
  fi
done

解决方案

bash provides C-like syntax for loop:

first=1
last=99999999
randomString="CXCXQOOPSOIS"

for ((val=$first; val<$last; val++))
do
  padVal=$( printf "%010d\n" $val )
  hash=$( echo -n $randomString$padVal | md5sum )
  if [[ "$hash" =~ ^000000) ]]; then
    echo "Number: $val"  >> log_000000
    echo "$val added to log - please check."
  fi
done

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