如何用for循环创建完美的急剧三角形？ [英] How Can I Make Perfect Acute Triangle with for loop?

问题描述

  0 
 1 1 
 2 2 2 
 3 3 3 3 
 4 4 4 4 4 
 5 5 5 5 5 $ 
 6 6 6 6 6 6 6 
 7 7 7 7 7 7 7 7 
 8 8 8 8 8 8 8 8 
 9 9 9 9 9 9 9 9 9 9 
  

但是当我想要超过10的时候，我的锐角三角形会变成这样：

  0 
 1 1 
 2 2 2 
 3 3 3 3 
 4 4 4 4 4 
 5 5 5 5 5 5 
 6 6 6 6 6 6 6 
 7 7 7 7 7 7 7 7 
 8 8 8 8 8 8 8 8 8 
 9 9 9 9 9 9 9 9 9 9 
 10 10 10 10 10 10 10 10 10 10 10 
 
 
 12 12 12 12 12 12 12 12 12 12 12 12 
  

我的代码如下

  public class Triangel {
 
 / ** 
 * @param args命令行参数
 * / 
 public static void main（String [] args）{
 
 for（int i = 20;我> 0; i  - ）{
 for（int j = i  -  1; j> 0; j  - ）{
 System.out.print（）; （i =< 9）{
 System.out.print（
）
（int k = 20; k> i  -  1; （+（20-i））; 
} else if（i> 9）{
 System.out.print（+（20-i））; 
} 
} 
 System.out.println（）; 
 
 
 
 
 
 $ b $ p 
 $ b $它完美的急性三角形，当我想9后打印？
 
 
 
注意：我认为if语句会帮助，但它似乎没有。 $ b 
解决方案
 改变Inner for循环： k = i-1  i> 9 和 i <9 ，所以11将被排除。我想你正试图管理两位数字和一位数字之间的空格。但是你可以使用单一的 i <= 10 和双倍空间for  i> 10  
  for（int k = 20; k> ; i  -  1; k  - ）{
 if（i <= 10）{
 System.out.print（+（20  -  i））; //单个空间$ b $如果（i> 10）{
 System.out.print（+（20-i））; // Double Space 
} 
} 
  
 注意：这个三角形可能看起来有些怪异  
Just for playing I tried to write a program so I can make a acute triangle with using a for loop, so my out put will like this:
                 0
                1  1
               2  2  2
              3  3  3  3
             4  4  4  4  4
            5  5  5  5  5  5
           6  6  6  6  6  6  6
          7  7  7  7  7  7  7  7
         8  8  8  8  8  8  8  8  8
        9  9  9  9  9  9  9  9  9  9
but when I want to go more than 10 my acute triangle gets messed up like this:
                 0
                1  1
               2  2  2
              3  3  3  3
             4  4  4  4  4
            5  5  5  5  5  5
           6  6  6  6  6  6  6
          7  7  7  7  7  7  7  7
         8  8  8  8  8  8  8  8  8
        9  9  9  9  9  9  9  9  9  9
       10  10  10  10  10  10  10  10  10  10  10


12           12           12           12           12           12           12           12           12           12           12           12           12
My code is as follows
public class Triangel {

    /**
     * @param args the command line arguments
     */
    public static void main(String[] args) {

        for (int i = 20; i > 0; i--) {
            for (int j = i - 1; j > 0; j--) {
                System.out.print(" ");
            }
            for (int k = 20; k > i - 1; k--) {
                if (i =< 9) {
                    System.out.print("           " + (20 - i));
                } else if (i > 9) {
                    System.out.print( "  "+(20 - i));
                }
            }
            System.out.println();
        }
    }
}
Any idea how I can make it perfect acute triangle when I wanna print after 9?


Note: I thought that the if statement would help, but it seems it does not.
解决方案
Just Change Inner for loop : here for k=i-1 as you are checking for i>9 and i<9 so 11 will be excluded. I guess you are trying to manage space between two digit and one digit number. But you can just use single for i<=10 and double space for i>10
       for (int k = 20; k > i - 1; k--) {
            if (i <= 10) {
                System.out.print(" "+(20 - i));//Single Space
            } else if (i > 10) {
                System.out.print("  "+(20 - i));//Double Space
            }
        }
NOTE:This triangle may look weird little bit

                        
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