如何在gnuplot中读取12h(AM / PM)时间格式 [英] How to read 12h (AM/PM) timeformat in gnuplot
问题描述
这些行包含一个时间戳和一个值。例如
2014年7月6日下午12点46分84.6
在Gnuplot中,我可以使用给定的格式标识符来读取时间戳。但是在上午或下午的时间不可能分开。
set timefmt%B%d,%Y at%H :%M
关于这个问题的任何建议?
awk'{time = $ 5; if(substr(time,6,2)==PM\
& amp; substr(time,1,2)< 12)add = 12; else add = 0; \
$ 5 = substr(time,1,2)+ addsubstr(time,3,3); \
print $ 0}'data
这样
2014年7月6日上午10:46 83.6
2014年7月6日下午12:46 84.6
2014年7月6日下午10:46 85.6
看起来就像
2014年7月6日10:46 83.6
2014年7月6日12:46 84.6
2014年7月6日22:46 85.6
在gnuplot中,您可以在绘制文件时动态地执行此操作。你可以这样做(注意我需要转义):
设置时间段%B%d,%Y在%H:%M
设置xdata时间
设置格式x%H:%M
plot< awk'{time = $ 5; if(substr(time,6,2)== \PM \\
& amp; substr(time,1,2)<12)add = 12; else add = 0; \
$ 5 = substr(time,1,2)+ add \\substr(time,3,3); \
print $ 0}'datau 1:6 wl
注意我假设00:15是00:15 AM如果你的输出是12:15 AM,那么你需要相应地修改这个脚本,如下所示:
if (substr(time,6,2)==AM& amp; substr(time,1,2)== 12)add = -12
I want to generate some nice graphs by using existing and auto generated data files. Unfortunately I cannot change the format of the files.
The lines contain a timestamp and a value. e.g.
July 06, 2014 at 12:46PM 84.6
In Gnuplot I can use the given format identifier to read the timestamp. But there is no possibility to separate between AM oder PM time.
set timefmt "%B %d, %Y at %H:%M"
Any suggestions on this problem?
The following awk
script will format your file:
awk '{time = $5; if(substr(time,6,2) == "PM" \
&& substr(time,1,2) < 12) add = 12; else add = 0; \
$5 = substr(time,1,2)+add "" substr(time,3,3); \
print $0}' data
so that
July 06, 2014 at 10:46AM 83.6
July 06, 2014 at 12:46PM 84.6
July 06, 2014 at 10:46PM 85.6
will look like
July 06, 2014 at 10:46 83.6
July 06, 2014 at 12:46 84.6
July 06, 2014 at 22:46 85.6
within gnuplot you can do this dynamically when plotting your file. You can do (note I need to escape the "
):
set timefmt "%B %d, %Y at %H:%M"
set xdata time
set format x "%H:%M"
plot "< awk '{time = $5; if(substr(time,6,2) == \"PM\" \
&& substr(time,1,2) < 12) add = 12; else add = 0; \
$5 = substr(time,1,2)+add \"\" substr(time,3,3); \
print $0}' data" u 1:6 w l
Note I am assuming that 00:15 is 00:15AM. If your output is 12:15AM then you need to modify the script accordingly. Something along these lines:
if(substr(time,6,2) == "AM" && substr(time,1,2) == 12) add = -12
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