Swift:格式字符串宽度 [英] Swift: Format String width
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问题描述
printf(% - 15s ,var);
这将创建15个字符的字段宽度。我做了很多Google搜索。我已经尝试过使用> COpaquepointer
以及字符串(格式:
以各种方式,没有运气。非常感谢。我可能错过了一些东西,当谷歌搜索。
解决方案
你最好自己动手
$ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $' (length - str0.characters.count),repeatedValue:Character())
str20r.appendContentsOf(str0)
//alpha
$ b $ // left justify
var str20l = str0
str20l.appendContentsOf(String(count:(length - str0.characters.count),repeatedValue:Character()))
//alpha
如果您需要更普遍的话
func formatString(str:String,fixLenght:Int,spacer:Character = Character(),justifyToTheRigth:Bool = false) - > String {
let c = str.characters .coun t
let start = str.characters.startIndex
let end = str.characters.endIndex
var str = str
if c> fixLenght {
switch justifyToTheRigth {
case true:
let range = start.advancedBy(c - fixLenght)..< end
return String(str.characters [range])
case false:
let range = start ..< end.advancedBy(fixLenght -c)
return String(str.characters [range])
}
} else {
var extraSpace = String(count:fixLenght - c,repeatedValue:spacer)
if justifyToTheRigth {
extraSpace.appendContentsOf(str)
return extraSpace
} else {
str.appendContentsOf(extraSpace)
return str
}
}
}
let str =ABCDEFGH
让s0 = formatString(str,fixLenght:3)
让s1 = formatString(str,fixLenght:3,justifyToTheRigth:true)
让s2 = formatString(str,fixLenght:10,spacer: - ))
let s3 = formatString(str,fixLenght:10,spacer:Charact er( - ),justifyToTheRigth:true)
print(s0)
print(s1)
print(s2)
print(s3)
打印
ABC
FGH
ABCDEFGH--
--ABCDEFGH
What I'm wanting to do is very simple in C/C++, Java, and so many other languages. All I want to do is be able to specify the width of a string, similar to this:
printf("%-15s", var);
This would create of a field width of 15 characters. I've done a lot of googling. I've tried using COpaquepointer
as well as String(format:
in various ways with no luck. Any suggestions would be greatly appreciated. I could have missed something when googling.
解决方案
You are better to do it yourself
let str0 = "alpha"
let length = 20
// right justify
var str20r = String(count: (length - str0.characters.count), repeatedValue: Character(" "))
str20r.appendContentsOf(str0)
// " alpha"
// left justify
var str20l = str0
str20l.appendContentsOf(String(count: (length - str0.characters.count), repeatedValue: Character(" ")))
// "alpha "
if you need something 'more general'
func formatString(str: String, fixLenght: Int, spacer: Character = Character(" "), justifyToTheRigth: Bool = false)->String {
let c = str.characters.count
let start = str.characters.startIndex
let end = str.characters.endIndex
var str = str
if c > fixLenght {
switch justifyToTheRigth {
case true:
let range = start.advancedBy(c - fixLenght)..<end
return String(str.characters[range])
case false:
let range = start..<end.advancedBy(fixLenght - c)
return String(str.characters[range])
}
} else {
var extraSpace = String(count: fixLenght - c, repeatedValue: spacer)
if justifyToTheRigth {
extraSpace.appendContentsOf(str)
return extraSpace
} else {
str.appendContentsOf(extraSpace)
return str
}
}
}
let str = "ABCDEFGH"
let s0 = formatString(str, fixLenght: 3)
let s1 = formatString(str, fixLenght: 3, justifyToTheRigth: true)
let s2 = formatString(str, fixLenght: 10, spacer: Character("-"))
let s3 = formatString(str, fixLenght: 10, spacer: Character("-"), justifyToTheRigth: true)
print(s0)
print(s1)
print(s2)
print(s3)
which prints
ABC
FGH
ABCDEFGH--
--ABCDEFGH
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