将列表写入到具有特定列数的行中 [英] Write to list to rows with specific number of columns

问题描述

我正在尝试将列表写入具有特定列数的行。例如，可以列出：

I'm trying to write a list to rows with a specific number of columns. For example, take the list:

data = [1.0, 2.0, 3.0, 4.0, 5.0, 6.0, 7.0, 8.0, 9.0, 10.0]

我想用这样的格式写出来： / p>

I would like to write this out with a format such that it looks like:

 1.0,  2.0,  3.0,
 4.0,  5.0,  6.0,
 7.0,  8.0,  9.0,
10.0,

我试过了下面的代码;但是，只能打印第一行：

I've tried the following code; however, can only get it to print the first line:

strformat = ['{'+str(i)+':>5.1f},' for i in range(0,3)]
strformat = ''.join(strformat).lstrip().rstrip() + '\n'
print strformat.format(*[x for x in data])

预先感谢！

推荐答案

def chunks(seq, n):
    # http://stackoverflow.com/a/312464/190597 (Ned Batchelder)
    """ Yield successive n-sized chunks from seq."""
    for i in xrange(0, len(seq), n):
        yield seq[i:i + n]

data = [1.0, 2.0, 3.0, 4.0, 5.0, 6.0, 7.0, 8.0, 9.0, 10.0]
for row in chunks(data, 3):
    print(',  '.join(map(str, row)))

$ b $

yields

1.0,  2.0,  3.0
4.0,  5.0,  6.0
7.0,  8.0,  9.0
10.0

或者更接近您的代码：

strformat = '\n'.join(
    ',  '.join('{:>5.1f}' for item in row) 
    for row in chunks(data, 3))
print(strformat.format(*data))

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