String.format（）获得最大值 [英] String.format() get maximum value

问题描述

我实现了一个计数器方法，它总是返回一个递增的数字。但用户可以提供希望的格式 ，2位数字，3位数字或任何他想要的。
格式是标准的String.format（）类型的字符串，如％02d 或％5d 。当达到最大值时，计数器应该被重置为0.

我怎样才能找出用给定的 format ？

  int counter = 0; 
 private String getCounter（String format）{
 if（counter> = getMaximum（format））{
 counter = 0; 
} 
 else {
 counter ++; 
} 
 return String.format（format，counter）; 
} 
 
 private int getMaximum（String format）{
 // TODO ??? 
 //格式可以是％02d =>应该返回100 
 //格式可以是％05d =>应该返回100000 
 
 
 
 $ div class =h2_lin>解决方案

没有验证这个代码，但沿线的东西应该与错误检查到位

  String str = fullresultText .replace（％，）.replace（d，）; 
 maxVal = Math.pow（10，Integer.parseInt（str））; 
  




I implemented a counter method that returns always an incremented number. But the user can give wished format, 2 digits, 3 digits or whatever he wants. The format is the standard String.format() type of String like %02d or %5d. When the maximum value is reached, the counter should be reset to 0.

How can I find out the max value that can be represented with the given format?

int counter = 0;
private String getCounter(String format){
    if(counter >= getMaximum(format)){
        counter = 0;
    }
    else {
        counter++;
    }
    return String.format(format, counter);
}

private int getMaximum(String format){
    //TODO ???
    //Format can be %02d => should return 100
    //Format can be %05d => should return 100000

}

解决方案

Haven't validated this code, but something along the lines of this should work with erro checking in place

    String str = fullresultText.replace ("%", "").replace("d", "");
    maxVal = Math.pow (10, Integer.parseInt (str));

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