在Scala中更好的字符串格式 [英] Better String formatting in Scala

问题描述

如果有太多参数， String.format 很容易变得太混乱。有一个更强大的方式来格式化一个字符串。像这样：

 This is＃{number} string.format（number - > 1）
  

或者是因为类型问题（ format 或者是更好的方法来做这件事情，比如说，我们可能需要做一个Map [String，Any]，我不认为这会让事情变得更糟）。这是：



  val number = 1 
< plain>这是{number}字符串< / plain>文本
  

尽管会污染名称空间吗？

编辑：

虽然简单的pimping可能在许多情况下，我也寻找的东西在同一方向Python的 format（）（参见： http://docs.python.org/release/3.1.2/library/string.html#formatstrings ）

解决方案

在Scala 2.10中，您可以使用字符串插值

  val height = 1.9d 
 val name =James
 println（f $ name％s是$ height％2.2f米高）//詹姆士身高1.90米
  

With too many arguments, String.format easily gets too confusing. Is there a more powerful way to format a String. Like so:

"This is #{number} string".format("number" -> 1)

Or is this not possible because of type issues (format would need to take a Map[String, Any], I assume; don’t know if this would make things worse).

Or is the better way doing it like this:

val number = 1
<plain>This is { number } string</plain> text

even though it pollutes the name space?

Edit:

While a simple pimping might do in many cases, I’m also looking for something going in the same direction as Python’s format() (See: http://docs.python.org/release/3.1.2/library/string.html#formatstrings)

解决方案

In Scala 2.10 you can use string interpolation.

val height = 1.9d
val name = "James"
println(f"$name%s is $height%2.2f meters tall")  // James is 1.90 meters tall

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