使用英特尔Fortran编译器避免在列表导向输出中使用换行符 [英] Avoid newline in list-directed output with Intel Fortran compiler

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问题描述



在Fortran中,列表导向的输出 write(*,*)的结果依赖于编译器。实际上,用代码:

 程式一
real(8),dimension(5):: (*,*)(r1(i),i = 1)b1 b1 b1(i)= sqrt(i * 10.0)
end do $ b $ 1,5)
结束程序一个



intel编译器ifort提供标准输出:

  3.16227769851685 4.47213602066040 5.47722530364990 
6.32455539703369 7.07106781005859

而gfortran给出了相当于一行的结果:

  3.1622776601683795 4.4721359549995796 5.4772255750516612 6.3245553203367590 7.0710678118654755 

我认为ifort每行最多写3个项目(浮动实数时)。
有什么办法可以让ifort输出像gfrotran一样,即避免换行符?
理想情况下,我想保持列表导向输出(*,*)指令,所以我正在寻找类似于编译器选项的东西, 。

解决方案

自从14版本开始,intel fortran编译器就有了-no-wrap-margin选项。 b

默认情况下,记录包装在80个字符之后;使用-no-wrap-margin消除了这种行为。


I have noticed the results of list-directed output write(*,*) in Fortran is compiler dependent.

Indeed, with the code:

program one
real(8), dimension(5):: r1
do i=1,5
    r1(i)=sqrt(i*10.0)
end do
write(*,*) (r1(i), i =1,5)
end program one

intel compiler ifort gives standard output broken by a newline:

   3.16227769851685        4.47213602066040        5.47722530364990     
   6.32455539703369        7.07106781005859     

while gfortran gives the equivalent one line result:

    3.1622776601683795        4.4721359549995796        5.4772255750516612        6.3245553203367590        7.0710678118654755     

I think that ifort is writing maximum 3 items per line (when floating real numbers). Is there any way to make the ifort output be like gfrotran, i.e. avoid the newline? Ideally, I would like to keep list-directed output (*,*) instructions, so I am looking for something like a compiler option or so, if any.

解决方案

Since verson 14, intel fortran compiler has the option -no-wrap-margin.

By default, the record is wrapped after 80 characters ; using -no-wrap-margin removes this behaviour.

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