如何使用sep打印可变数量的元素并结束？ [英] How to print variable number of elements using sep and end?

问题描述

我一直试图用 sep =''来区分彼此之间的数字，但是除非我用 end = 。
然而，当我用 end =切换 sep =''时，它可以正常工作。
那么，我做错了什么？
另外，如何在+符号之间分隔数字，而不会出现在最后？

I've been trying to use the sep='' to separate the numbers in between each other but they never separate unless I use end="". However, when I switch sep='' with end="" it works properly. So, what am I doing wrong? Also, how do I separate the numbers in between with a "+" symbol without having it appear at the end?

谢谢！

Thanks!

#Counter
numcounter=0
#Get starting integer from user

s_num=int(input("Please enter a valid starting integer number: "))

#Get ending integer from user

e_num=int(input("Please enter a valid ending integer number: "))

#For loop

for numbers in range (s_num,e_num+1):
    numcounter+=numbers
    print(numbers, sep='')

这是输出：

This was the output:

Python 3.4.1 (v3.4.1:c0e311e010fc, May 18 2014, 10:38:22) [MSC v.1600 32 bit (Intel)] on win32
Type "copyright", "credits" or "license()" for more information.
>>> ================================ RESTART ================================
>>> 
Please enter a valid starting integer number: 1
Please enter a valid ending integer number: 5
1
2
3
4
5

推荐答案

如果您查看 print - 功能。它需要一个可变数字来打印输出，由给定的 sep 分隔，并以 end 结尾。因此，您可以简单地使用 *语法将序列传递给 print 。简单地说：

If you look at the documentation for the print-function. It takes a variable numbers to print out separated by the given sep and ended with end. So you can simply use the *syntax to pass your sequence to print. Simply:

>>> print(*range(1,5))
1 2 3 4
>>> print(*range(1,5), sep='+')
1+2+3+4
>>> print(*range(1,5), sep='+', end='=' + str(sum(range(1,5))))
1+2+3+4=10

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