Rails 3提交一个包含多个记录的表单 [英] Rails 3 submit a form with multiple records

问题描述

我是新手，所以这可能是一个基本问题。我正在尝试创建一个表单，用户可以一次创建3条记录。我希望用户只需点击一次提交按钮。我向我的评论模型提交了名称，评论和评分。目前，只有最后一条记录被输入到数据库中。

 <％= form_for（[@ user，@ review]） do | f | ％GT; 
< table> 
< tr> 
< td> Rank< / td> 
< td>名称< / td> 
< td>评论< / td> 
< / tr> 
< tr> 
< td> 1< / td> 
< td><％= f.text_field：name％>< / td> 
< td><％= f.text_field：comment％>< / td> 
 <％= f.hidden_​​field：rating，：value => 5％> 
< / tr> 
< tr> 
< td> 2< / td> 
< td><％= f.text_field：name％>< / td> 
< td><％= f.text_field：comment％>< / td> 
 <％= f.hidden_​​field：rating，：value => 3％> 
< / tr> 
< tr> 
< td> 3< / td> 
< td><％= f.text_field：name％>< / td> 
< td><％= f.text_field：comment％>< / td> 
 <％= f.hidden_​​field：rating，：value => 1％> 
< / tr> 
< / table> 
< div class =actions> 
 <％= f.submitCreate my top 3％> 
< / div> 
<％end％> 
  

任何建议表示赞赏。谢谢。

解决方案

我建议使用 fields_for p>

 <％= form_for（[@ user，：reviews]）do | f | ％GT; 
<％@ reviews.each do | review | ％GT; 
 <％= fields_for review do | r | ％GT; 
 <％=呈现reviews / form，：r => r％> 
<％end％> 
<％end％> 
<％end％> 
  

要做到这一点，您需要在控制器中构建尽可能多的审阅对象：

  def new 
＃你也可以在before_filter中找到这个... 
 @user = User .find（params [：id]）
 @reviews = Array.new（3）{@ user.reviews.build} 
 end 
  

这会为此用户创建新的实例的审阅记录，这与新的记录不同。实例只是Ruby对象。现在，因为您已三次调用 @ user.reviews.build ，您会在视图中看到三条评论。

（$ params [：id]）

@reviews = Review.create（params [：评论]）
＃验证传入参数的更多逻辑
end

这将创建三个新的 Review 对象，并将它们链接到 @user ，假设所有三个都是有效的。

I'm new to rails so this is probably a basic question. I am trying to create a form where the user can create 3 records at once. I want the user to only have to click the submit button once. I'm submitting to my Review model a name, comment, and rating. Currently, only the last record is entered into the database.

<%= form_for([@user,@review]) do |f| %>
<table>
  <tr>
    <td>Rank</td>
    <td>Name</td>
    <td>Comment</td>
  </tr>
  <tr>
    <td>1</td>
    <td><%= f.text_field :name %></td>
    <td><%= f.text_field :comment %></td>
    <%= f.hidden_field :rating, :value=> "5" %>
  </tr>
  <tr>
    <td>2</td>
    <td><%= f.text_field :name %></td>
    <td><%= f.text_field :comment %></td>
    <%= f.hidden_field :rating, :value=> "3" %> 
  </tr>
  <tr>
    <td>3</td>
    <td><%= f.text_field :name %></td>
    <td><%= f.text_field :comment %></td>
    <%= f.hidden_field :rating, :value=> "1" %>
  </tr>
</table>
  <div class="actions">
    <%= f.submit "Create my top 3" %>
  </div>
<% end %>

Any advice is appreciated. Thanks.

解决方案

I would recommend using fields_for for this:

<%= form_for([@user, :reviews]) do |f| %>
  <% @reviews.each do |review| %>
    <%= fields_for review do |r| %>
      <%= render "reviews/form", :r => r %>
    <% end %>
  <% end %>
<% end %>

To make this work, you will need to build as many review objects as you require in your controller:

def new
  # you could also have this in a before_filter...
  @user = User.find(params[:id])
  @reviews = Array.new(3) { @user.reviews.build }
end

This would create new instances of review records for this user, which is different from new records. Instances are simply Ruby objects. Now because you've called @user.reviews.build three times, you'll see three reviews in your view.

def create
  @user = User.find(params[:id])

  @reviews = Review.create(params[:reviews])
  # Some more logic for validating the parameters passed in
end

This will create three new Review objects and link them to @user, assuming all three are valid.

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