PHP表单动作PHP自我 [英] php form action php self

问题描述

 < form name =form1id =mainFormmethod = postenctype =multipart / form-dataaction =<？php echo $ _SERVER ['PHP_SELF'];？>> 
 
   

在表单操作中，我想使用页面名称带参数。如 house.php？p_id = 10111 。但$ _SERVER ['PHP_SELF']只给出 house.php （我的页面完整url为 house.php？p_id = 10111 这样）请帮我解决这个问题。感谢。

解决方案

如何将它留空，这有什么不妥？

 < form name =form1id =mainFormmethod =postenctype =multipart / form-dataaction => 
 
< / form> 
  

另外，您可以省略操作属性，它将按预期工作。

I have a php form like this.

<form name="form1" id="mainForm" method="post"enctype="multipart/form-data" action="<?php echo $_SERVER['PHP_SELF'];?>">

</form

In form action I want to use page name with parameters. like house.php?p_id=10111 . But $_SERVER['PHP_SELF'] gives only the house.php (My page full url is house.php?p_id=10111 like this) Please help me to solve this problem. thanks.

解决方案

How about leaving it empty, what is wrong with that?

<form name="form1" id="mainForm" method="post" enctype="multipart/form-data" action="">

</form>

Also, you can omit the action attribute and it will work as expected.

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