php http请求内容原始数据enctype = multipart / form-data [英] php http request content raw data enctype=multipart/form-data
问题描述
我目前正在编写两个类：HttpRequest和HttpResponse。
我想编写自己的HTTP类。
使用enctype = multipart / form-data格式的POST方法遇到问题：经过长时间的研究和搜索，我发现我必须使用 file_get_contents（php： //输入）来获取请求内容。
当我测试它时，我有一个空字符串 var_dump（file_get_contents（php：// input））。
我无法访问server / php配置。
我使用以下代码进行测试：
<？php
$ input = file_get_contents（'php：// input'）;
var_dump（$ input）;
？>
< html>
< body>
< form action =./method =postenctype =multipart / form-data>
< label for =file>档案名称：< / label>
< input type =textname =namenid =nameid/>< br />
< input type =filename =fileid =file>< br>
< input type =filename =file2id =file2>< br>
< input type =submitname =submitvalue =Submit>
< / form>
< / body>
< / html>
提交后，我得到如下结果： string（0） 。
这很明显，因为php：//输入不适用于enctype =multipart / form-data表单。
我想要一些东西例如：
------------------------ ----- 19972703421793859182225487886
Content-Disposition：form-data; name =namen
ds
----------------------------- 19972703421793859182225487886
Content-Disposition：form-data; NAME = 文件; filename =toto.xml
Content-Type：text / xml
<？xml version =1.0encoding =UTF-8？>
<多多>< /多多>
----------------------------- 19972703421793859182225487886
Content-Disposition：form-data; NAME = file2的; filename =
Content-Type：application / octet-stream
--------------------- -------- 19972703421793859182225487886
内容处理：form-data; name =submit
提交
----------------------------- 19972703421793859182225487886--
是否适用于任何请求方法？或者我错了？
我在这里找到一个明显的问题：为什么还要努力去解析它呢？通过使用$ _POST [] / $ _FILES [] ..
，您可以轻松使用数据。您仍然可以围绕这些值构建自己的类，而不是你自己的类尝试完成与php编译器已经为你做的相同的数据数组。
为了给你一个有效的答案：我不知道一种获取你的php：//输入的方法，因为它可能被PHP编译器读取，因此你在流的末尾（加上：它是只读的，因此可能无法将指针重置为流的开始）。
I'm currently coding two classes: HttpRequest and HttpResponse. I want to code my own HTTP classes.
I'm encountering an issue with a POST method using a form with enctype=multipart/form-data: I can't get the request contents.
After a long research and searchs, I've found I have to use file_get_contents("php://input") to get the request content.
When I test it, I have an empty string var_dump(file_get_contents("php://input")).
I have no access to server/php configuration.
I'm testing with the following code :
<?php
$input = file_get_contents('php://input');
var_dump($input);
?>
<html>
<body>
<form action="./" method="post" enctype="multipart/form-data">
<label for="file">Filename:</label>
<input type="text" name="namen" id="nameid" /><br/>
<input type="file" name="file" id="file"><br>
<input type="file" name="file2" id="file2"><br>
<input type="submit" name="submit" value="Submit">
</form>
</body>
</html>
And after submitting, I have this result : string(0) "".
It's obvious because php://input doesn't work with enctype="multipart/form-data" forms.
I'd like to have something like :
-----------------------------19972703421793859182225487886
Content-Disposition: form-data; name="namen"
ds
-----------------------------19972703421793859182225487886
Content-Disposition: form-data; name="file"; filename="toto.xml"
Content-Type: text/xml
<?xml version="1.0" encoding="UTF-8"?>
<Toto></Toto>
-----------------------------19972703421793859182225487886
Content-Disposition: form-data; name="file2"; filename=""
Content-Type: application/octet-stream
-----------------------------19972703421793859182225487886
Content-Disposition: form-data; name="submit"
Submit
-----------------------------19972703421793859182225487886--
Is a way it works for any request method ? Or am I wrong ?
I'm going for the obvious one here: why even bother trying to parse this yourself? The data is within your range with the easy use of $_POST[] / $_FILES[] ..
You can still build your own class around those values instead of having your own classes try to accomplish the same data array as the php-compiler already did for you.
In order to give you a valid answer: I don't know of a way to get your php://input back, as it is probably read by the PHP compiler and therefore you are at the end of the stream ( plus: it is read-only so there is probably no way to reset the pointer to the start of the stream ).
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