使用PHP从MySQL数据库获取数据，将其显示在表单中进行编辑 [英] Fetching data from MySQL database using PHP, Displaying it in a form for editing
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问题描述
我是一个新手，并且编写了下面的代码来从MySQL数据库中获取用户数据，并将其显示在一个表单中进行编辑和保存。问题是，它不起作用。任何帮助将不胜感激。
I'm a newbie to this and wrote the code below to fetch user data from a MySQL Database and display it in a form for editing and saving. Problem is, it does not work. Any help will be appreciated.
<html>
<head>
<title> Delegate edit form</title>
</head>
<body>
Delegate update form <p>
<?php
$usernm = "root";
$passwd = "";
$host = "localhost";
$database = "swift";
//$Name=$_POST['Name'];
//$Username=$_POST['User_name'];
//$Password=$_POST['Password'];
mysql_connect($host,$usernm,$passwd);
mysql_select_db($database);
$sql = "SELECT * FROM usermaster WHERE User_name='$Username'";
$result = mysql_query($sql) or die(mysql_error());
while ($row = mysql_fetch_array($result))
{
$Name = $row['Name'];
$Username = $row['User_name'];
$Password = $row['User_password'];
}
?>
<form action="Delegate_update.php" method="post">
Name
<input type="text" name= "Name" value= "<?php echo $row ['Name']; ?> "size=10>
Username
<input type="text" name= "Username" value= "<?php echo $row ['Username']; ?> "size=10>
Password
<input type="text" name= "Password" value= "<?php echo $row ['Password']; ?>" size=17>
<input type="submit" name= "submit" value="Update">
</form>
</body>
</html>
推荐答案
播放这段代码。关注这个概念，在必要时进行编辑，以便它可以
Play around this piece of code. Focus on the concept, edit where necessary so that it can
<html>
<head>
<title> Delegate edit form</title>
</head>
<body>
Delegate update form </p>
<meta name="viewport" content="width=device-width; initial-scale=1.0">
<link rel="shortcut icon" href="images/favicon.ico" type="image/x-icon" />
<link href='http://fonts.googleapis.com/css?family=Droid+Serif|Ubuntu' rel='stylesheet' type='text/css'>
<link rel="stylesheet" href="css/normalize.css">
<link rel="stylesheet" href="js/flexslider/flexslider.css" />
<link rel="stylesheet" href="css/basic-style.css">
<script src="js/libs/modernizr-2.6.2.min.js"></script>
</head>
<body id="home">
<header class="wrapper clearfix">
<nav id="topnav" role="navigation">
<div class="menu-toggle">Menu</div>
<ul class="srt-menu" id="menu-main-navigation">
<li><a href="Swift_Landing.html">Home page</a></li>
</header>
</section>
<style>
form label {
display: inline-block;
width: 100px;
font-weight: bold;
}
</style>
</ul>
<?php
session_start();
$usernm="root";
$passwd="";
$host="localhost";
$database="swift";
$Username=$_SESSION['myssession'];
mysql_connect($host,$usernm,$passwd);
mysql_select_db($database);
$sql = "SELECT * FROM usermaster WHERE User_name='$Username'";
$result = mysql_query ($sql) or die (mysql_error ());
while ($row = mysql_fetch_array ($result)){
?>
<form action="Delegate_update.php" method="post">
Name
<input type="text" name="Namex" value="<?php echo $row ['Name']; ?> " size=10>
Username
<input type="text" name="Username" value="<?php echo $row ['User_name']; ?> " size=10>
Password
<input type="text" name="Password" value="<?php echo $row ['User_password']; ?>" size=17>
<input type="submit" name="submit" value="Update">
</form>
<?php
}
?>
</p>
</body>
</html>
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