连接PHP源代码并提交表单到MySQL数据库 [英] Connecting PHP source code and submit form to MySQL Database
本文介绍了连接PHP源代码并提交表单到MySQL数据库的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
我试图学习PHP，我试图用我的PHP代码连接一个MySQL数据库来创建一个允许我将数据输入到数据库的提交表单。我的问题是，源代码正在连接，但HTML不会将变量发布到PHP文件。
这是我的HTML源代码
< HTML>
< head>
< title>表格输入资料< / title>
< / head>
< body>
< table border =1>
< tr>
< td align =center>表单输入员工数据< / td>
< / tr>
< tr>
< td>
< table>
< form action =input.phpmethod =POST>
< tr>
< td>名称< / td>
< td>< input type =textname =namesize =20>
< / td>
< / tr>
< tr>
< td>地址< / td>
< td>< input type =textname =addresssize =40>
< / td>
< / tr>
< tr>
< td>< / td>
< td align =right>< input type =submit
name =submitvalue =Sent>< / td>
< / tr>
< / table>
< / td>
< / tr>
< / table>
是我的PHP源代码
<？php
$ user_name =fees0_14446440;
$ password =********;
$ database =fees0_14446440_addressbook;
$ server =sql107.0fees.net;
mysql_connect（$ server，$ user_name，$ password）;
mysql_select_db（$ database）; b
$ '$ name'，
'$ address'）;
$ result = mysql_query（$ order）;
if（$ result）{
echo（< br>输入数据成功）;
$ b} else {
echo（< br>输入数据失败）;
}
？>
解决方案
您可以在PHP的 $ _POST 变量。它应该包含所有通过POST方法传递的值。
$ name = $ _POST [name];
I'm trying to learn PHP and I'm trying to connect a MySQL database with my PHP code to make a submit form that lets me input data into the database. My problem is that the source code is connecting but the HTML isn't posting the variables to the PHP file. I could really use some help.
This is my HTML source code
<html>
<head>
<title>Form Input Data</title>
</head>
<body>
<table border="1">
<tr>
<td align="center">Form Input Employees Data</td>
</tr>
<tr>
<td>
<table>
<form action="input.php" method="POST">
<tr>
<td>Name</td>
<td><input type="text" name="name" size="20">
</td>
</tr>
<tr>
<td>Address</td>
<td><input type="text" name="address" size="40">
</td>
</tr>
<tr>
<td></td>
<td align="right"><input type="submit"
name="submit" value="Sent"></td>
</tr>
</table>
</td>
</tr>
</table>
And this is my PHP source code
<?php
$user_name = "fees0_14446440";
$password = "********";
$database = "fees0_14446440_addressbook";
$server = "sql107.0fees.net";
mysql_connect("$server","$user_name","$password");
mysql_select_db("$database");
$order = "INSERT INTO Trial
(name, address)
VALUES
('$name',
'$address')";
$result = mysql_query($order);
if($result){
echo("<br>Input data is succeed");
} else{
echo("<br>Input data is fail");
}
?>
解决方案
You can find the POST data in PHP's $_POST variable. It should hold all the values that were passed via the POST method.
$name = $_POST["name"];
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