将数据传递给现有表单 [英] Pass data to a existing form
问题描述
我有一个程序需要来自另一个表单的数据,我需要通过它而不创建第一个表单的新实例。我怎么能这样做?
ex。
Form2 f2 = new Form2();
f2.showdialog();
当f2显示时,它们是带有项目的列表视图,当我点击一个项目时,我想要项目被发送回第一个窗体而不关闭窗体2并且没有实例化一个新的窗体1.
您正在寻找某种
公共事件EventHandler MyButtonClicked;
在使用ShowDialog()之前;
Form2 f2 = new Form2();
f2.MyButtonClicked + = f2_MyButtonClicked;
f2.showdialog();
处理事件的地方
$ $ $ $ b $ $ $ $
$ $ $ $
$ $ $ b $ $你可以从发件人处获得f2。
Form2 f2 =(Form2)sender;
抛出新的NotImplementedException();
}
当您在Form2中点击您引发活动的按钮时。
void myButtonClicked(object sender,EventArgs e)
{
if(MyButtonClicked!= null)
{
MyButtonClicked(this,new EventArgs());
code
$ b如果你想了解更多关于事件的信息, at。
http://msdn.microsoft.com/zh-CN/library/aa645739%28v=vs.71%29.aspx
I have a program that needs a data from another form and I need to pass it without creating a new instance of the first form. how can i do that?
ex.
Form2 f2 = new Form2();
f2.showdialog();
when f2 shows, their is an listview with items, when I click on an item, I want the item to be sent back to the first form without closing form2 and without instantiating a new Form1.
解决方案 You are looking for some kind of event.
public event EventHandler MyButtonClicked;
And before you use ShowDialog();
Form2 f2 = new Form2();
f2.MyButtonClicked += f2_MyButtonClicked;
f2.showdialog();
And somewhere to handle the event
void f2_MyButtonClicked(object sender, EventArgs e)
{
//Here you want to grab your list. You can get f2 from sender.
Form2 f2 = (Form2)sender;
throw new NotImplementedException();
}
When you in Form2 click the button you raise the event.
void myButtonClicked(object sender, EventArgs e)
{
if (MyButtonClicked != null)
{
MyButtonClicked(this, new EventArgs());
}
}
If you want to read more on events have a look at.
http://msdn.microsoft.com/en-us/library/aa645739%28v=vs.71%29.aspx
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