提交后，表单会保留在同一页面上 [英] Form stay on same page after submit

问题描述

即使在显示警告消息并且返回错误代码显然存在之后，我的页面仍会继续提交。我在这里做错了什么？

 函数validateForm（）{
 var selected =; 
 var radios = document.getElementsByName（special）; 
 var len = document.getElementsByName（special）。length; 
 var i; 
 $ b $ for（i = 0; i< len; i ++）{
 if（radios [i] .checked）{
 selected = radios [i] .value; 
休息; 
} 
 if（selected ==）{
 alert（必须选择选项。）; 
返回false; 
} 
 else {
 return true; 
 
 
 
 
 
< p>您想特别优惠发送给您的电子邮件吗？< / p> 
< input type =radioname =specialvalue =Yes/>是
< input type =radioname =specialvalue =No/>否LT峰; br /> 
< input type =submit/> 
< input type =reset/> 
< / form> 
  

解决方案

您必须像这样说

  onsubmit =return validateForm（）; 
  

而不是

 的onsubmit = validateForm（）; 
  

更新的演示版本

这是因为您正在检查中选定的的值c $ c> for 循环，所以第一次它的值是第二次变成否。

My page keeps submitting even after it shows the alert message and the return false code is clearly present. What am I doing wrong here?

     function validateForm () {
        var selected = "";
        var radios = document.getElementsByName("special");
        var len = document.getElementsByName("special").length;
        var i;

        for (i = 0; i < len; i++) {
            if(radios[i].checked) {
                selected = radios[i].value;
                break;
            }
            if(selected == "") {
                alert("Must select option.");
                return false;
            }
            else {
                return true;
            }
        }
     }

    <form action="FormProcessor.html" method="post" onreset="blank();" onsubmit="validateForm();" name="myForm">
            <p>Would you like special offers sent to you e-mail?</p>
            <input type="radio" name="special" value="Yes"/>Yes
            <input type="radio" name="special" value="No"/>No<br/>
            <input type="submit"/>
            <input type="reset"/>
    </form>

解决方案

You have to just say like this

onsubmit="return validateForm();"

instead of

onsubmit="validateForm();"

updated demo

That was because you were checking the value of selected in for loop, so for first time it's value is "" second time it's become No.

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