变形的矩形具有递减趋势 [英] deformed rectangulars with decreasing trend

问题描述

我必须使用python（matplotlib）实现一些像这样的图片。

i have to implement some figures like that on the Picture with python (matplotlib).

有没有人知道我能做到这一点？我尝试使用多边形来创建这些变形的矩形，例如像这样：

Has anyone an idea how i could achieve this? I tried to work with polygons to create these deformed rectangulars, for example like this:

import matplotlib.pyplot as plt

plt.axes()

points = [[x, y]]    
polygon = plt.Polygon(points)

plt.show()

但它只显示一个坐标系，没有别的东西，当我输入x，y点以获得变形的矩形。

but it just shows a coordinate system and nothing else when I type in the x,y points to get a deformed rectangular.

我现在使用了@ImportanceOfBeingErnest的答案，但是抛出一个错误

I now used the answer by @ImportanceOfBeingErnest, but throws an error

有没有人有一个想法来自哪里？

Does anyone have an idea where this comes from?

推荐答案

这是一种添加多边形的方法到一个matplotlib轴。多边形是 matplotlib.patches.Polygon 的一个实例，它使用 ax.add_patch 附加到轴上。

Here is a way to add a polygon to a matplotlib axes. The polygon is an instance of matplotlib.patches.Polygon and it is appended to the axes using ax.add_patch.

由于matplotlib不会自动缩放包含补丁的轴，因此需要设置轴限制。

Since matplotlib does not autoscale the axes to include patches, it is necessary to set the axis limits.

import matplotlib.pyplot as plt
import matplotlib.patches

x = [1,10,10,1,1]
y = [2,1,5,4,2]
points = list(zip(x,y))

polygon = matplotlib.patches.Polygon(points, facecolor="#aa0088")

fig, ax = plt.subplots()
ax.set_aspect("equal")
ax.add_patch(polygon)

ax.set_xlim(0,11)
ax.set_ylim(0,6)
plt.show()

这篇关于变形的矩形具有递减趋势的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！