为什么此代码散列为空？ [英] Why does this code hash null?

问题描述

以下代码传递用户名检查，但密码失败。

正如您所看到的，哈希值会被回显，但由于某些原因，它们会输出 e3b0c44298fc1c149afbf4c8996fb92427ae41e4649b934ca495991b7852b855 ，这是 sha256sum / dev / null 。由于密码似乎没有回应，我只能假设它不能得到POST，但为什么？

登录

 < form action =dologinmethod =post> 
用户名：< input type =textname =username> 
密码：< input type =passwordname =password> 
< input type =submit> 
< / form> 
  

dologin

  if（$ _POST [username] == $ actualusername）{
 //哈希密码
 $ hashedpassword = hash（'sha256'，$ _POST [password]）; 
 echo $ _POST [password]; 
 echo $ hashedpassword; 
 if（$ hashedpassword == $ actualpassword）{
 echo'< h2> Logged in< / h2>'; 
} else {
 echo'< h2>密码错误< / h2>'; 
 echo $ hashedpassword; 
} 
} else {
 echo'< h2>不正确的用户名< / h2>'; 
} 
  

解决方案

你有问题吗？
此外，您可以使用

  isset（$ _ POST [blabla]）
  

测试该值是否设置在 $ _ POST中中。

The following code passes on the username check, but fails on the password.

As you can see, the hashes are echoed, but for some reason, they output e3b0c44298fc1c149afbf4c8996fb92427ae41e4649b934ca495991b7852b855, which is the sha256sum of /dev/null. As the password does not seem to echo at all, i can only assume it cannot get the POST, but why?

login

<form action="dologin" method="post">
Username: <input type="text" name="username">
Password: <input type="password" name="password">
<input type="submit">
</form>

dologin

    if ( $_POST[username] == $actualusername ) {
        // Hash the password
        $hashedpassword = hash('sha256', $_POST[password]);
        echo $_POST[password];
        echo $hashedpassword;
        if ( $hashedpassword == $actualpassword ) {
            echo '<h2>Logged in</h2>';
        } else {
        echo '<h2>Incorrect password</h2>';
        echo $hashedpassword;
        }
    } else {
        echo '<h2>Incorrect username</h2>';
    }

解决方案

Does closing the input tags solve you problem? Also, you can use

isset($_POST["blabla"])

To test if the value is set in $_POST.

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