HTML表单提交按钮不会写入$ _POST [英] HTML form submit button does not write in $_POST

问题描述

我想要一个带有4个提交按钮的表单。一旦他们中的任何一个被按下，他们的shell将调用具有不同内容的相同页面。为了确定它是哪一个内容，我将编写一个PHP脚本，但我还没有到。我的问题是，我需要传递值。

I want a form with 4 submit buttons. Once any of them is pressed, they shell call the same page with different content. To determine which content it is, I will write a PHP Script, but I have not come that far yet. My Problem on the way is, that I need to pass the value along.

我在这里找到了我的问题的答案（以一种形式提交两个按钮）。我复制并调整了代码，但它不起作用。
当我想用我定义的名称访问$ _POST数组时，它说它是一个未知的索引。这是我迄今为止的相关代码。

I found an answer to my question in here ( Two submit buttons in one form ). I copied and adjusted the code but it is not working. When I want to access the $_POST array with my defined name, it says it is an unknown index. This is my relevant code so far.

<div>
    <form action="nutzerverwaltung.php" method="post">
        <input type="submit" class="nv_select" name="nv_select" value="Nutzer hinzufuegen" />
        <input type="submit" class="nv_select" name="nv_select" value="Nutzer loeschen" />
        <input type="submit" class="nv_select" name="nv_select" value="Nutzer bearbeiten" />
        <input type="submit" class="nv_select" name="nv_select" value="Alle Nutzer anzeigen" />
    </form>
    <br />
</div>

<?php if ($_POST["nv_select"] == "Nutzer hinzufuegen") echo "Hallo"; ?>

我做错了什么？

John

推荐答案

也许你想写名字 = nv_select。你忘了平等。当然，名称属性应该是不同的nv_select1，nv_select2等。

Maybe you want to write name = "nv_select". You forget equal. Of course name atributes should be different nv_select1, nv_select2 etc.

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