涉及整数和实数操作数的算术 [英] Arithmetic involving integer and real operands

问题描述

在Fortran中，涉及整数和 real 操作数的算术总是携带 通过将整数操作数转换为与实际操作数相同类型的实际值？或者是否有任何异常？

解决方案

这是在Ch。 7.1.5.1 rel =nofollow > Fortran 2008 Standard ：

摘自7.15：

 内部运算符类型类型
 op x1 x2 [x1] op x2 
 --------------- ------------------------------------------- 
 II，R ，ZI，R，Z 
二进制+， - ，*，/，** RI，R，ZR，R，Z 
 ZI，R，ZZ，Z，Z 
  

[b]

注意：符号I，R， Z，C和L分别表示整数，实数，
复数，字符和逻辑类型。如果给出了x 2的多个
类型，则操作结果的类型是
，在下一列的相同位置给出。

所以是的，在你的情况下它被转换为 real 。

In Fortran, will arithmetic involving an integer and real operand be always carried out by converting the integer operand to a real value of the same kind as the real operand? Or is there any exception?

解决方案

This is defined in Ch. 7.1.5.1 "Intrinsic operation classification" of the Fortran 2008 Standard:

Excerpt from NOTE 7.15:

Intrinsic operator      Type of     Type of       Type of
op                        x1          x2        [x1] op x2
----------------------------------------------------------
                           I        I, R, Z       I, R, Z
Binary +, –, *, /, **      R        I, R, Z       R, R, Z
                           Z        I, R, Z       Z, Z, Z

[...]

Note: The symbols I, R, Z, C, and L stand for the types integer, real, complex, character, and logical, respectively. Where more than one type for x 2 is given, the type of the result of the operation is given in the same relative position in the next column.

So yes, it is converted to real in your case.

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