检查FTP上是否存在文件 - 不知道文件的名称 [英] Check if file exists on FTP - Don't know the name of the file

问题描述

我在FTP服务器上收到一个文件，文件的名字是动态生成的。我试图编写一个程序来检查服务器上是否存在任何文件。

  string userName = Dts.Variables [User :: SFTPUsername] Value.ToString（）; 
 string password = Dts.Variables [User :: SFTPPassword]。Value.ToString（）; 
 ** string fileName = Dts.Variables [User :: FilePattern]。Value.ToString（）; ** 
 string ftpURL = String.Format（ftp：//11.11.11/upload / {0}，fileName）; 
 
 WebClient请求=新的WebClient（）; 
 request.Credentials = new NetworkCredential（userName，password）; 
 
 
 FtpWebRequest ftpRequest =（FtpWebRequest）WebRequest.Create（ftpURL）; 
 ftpRequest.Method = WebRequestMethods.Ftp.GetFileSize; 
 ftpRequest.Credentials = new NetworkCredential（userName，password）; 
 
 using（FtpWebResponse ftpResponse =（FtpWebResponse）ftpRequest.GetResponse（））
 {
 byte [] newFileData = request.DownloadData（ftpURL.ToString（））; 
 string fileString = System.Text.Encoding.UTF8.GetString（newFileData）; 
 
 string strexist = String.Format（exist）; 
 MessageBox.Show（strexist）; 
 Dts.Variables [User :: FileExists]。Value = true; 
} 
  

只有在指定文件名时才能正常工作。无论如何，我可以做一个通配符搜索（* .txt）或搜索任何文件是否在上传文件夹？

任何帮助赞赏!!

解决方案

您可以从 FTP 列出文件名。像下面这样...

  FtpWebRequest请求=（FtpWebRequest）WebRequest.Create（ftpURL）; 
 request.Method = WebRequestMethods.Ftp.ListDirectory; 
 
 FtpWebResponse response =（FtpWebResponse）request.GetResponse（）; 
 using（Stream respStream = response.GetResponseStream（））
 {
 StreamReader reader = new StreamReader（respStream）; 
 //从响应
读取每个文件的名称（string fname = reader.ReadLine（）; fname！= null; fname = reader.ReadLine（））
 {
 //将文件名添加到列表中
 
 
 code 
 
 
 
如果列表计数为0，那么没有可用的文件。 
 
 
 
使用 foreach循环迭代列表值 foreach循环。并将上面的代码作为一种方法。将文件名传递给方法。
 
 
 
您也可以确保特定文件名存在或不存在于列表中。
 
 
 
 注意：在上面的代码中，不需要向 Url 提供文件名。  
I receive a file on the FTP server, the name of the file is generated dynamically. I am trying to write a program to check if any file exists on the server.
        string userName = Dts.Variables["User::SFTPUsername"].Value.ToString();
        string password = Dts.Variables["User::SFTPPassword"].Value.ToString();
        **string fileName = Dts.Variables["User::FilePattern"].Value.ToString();**
        string ftpURL = String.Format("ftp://11.11.11/upload/{0}", fileName);

            WebClient request = new WebClient();
            request.Credentials = new NetworkCredential(userName, password);


            FtpWebRequest ftpRequest = (FtpWebRequest)WebRequest.Create(ftpURL);
            ftpRequest.Method = WebRequestMethods.Ftp.GetFileSize;
            ftpRequest.Credentials = new NetworkCredential(userName, password);

            using (FtpWebResponse ftpResponse = (FtpWebResponse)ftpRequest.GetResponse())
            {
                byte[] newFileData = request.DownloadData(ftpURL.ToString());
                string fileString = System.Text.Encoding.UTF8.GetString(newFileData);

                string strexist = String.Format("exist");
                MessageBox.Show(strexist);
                Dts.Variables["User::FileExists"].Value = true;
            }
This works well only when I specify the "fileName". Is there anyway I can do a wildcard search ("*.txt") or search if anyfile is in the upload folder?

Any help appreciated!!
解决方案
You can list out the file names from the FTP. Like Below...
            FtpWebRequest request = (FtpWebRequest)WebRequest.Create(ftpURL);
            request.Method = WebRequestMethods.Ftp.ListDirectory; 

            FtpWebResponse response = (FtpWebResponse) request.GetResponse();
            using (Stream respStream = response.GetResponseStream())
            {
                StreamReader reader = new StreamReader(respStream);
                //Read each file name from the response
                for (string fname = reader.ReadLine(); fname != null; fname = reader.ReadLine())
                {
                    // Add the file name into a list
                }
            }
If the list count is 0 then there is no file available. Also you will get the each file name in a list from the single request.

Iterate the list values using foreach loop. And make the above code as a method. Pass the File name to the method.

You can also do make sure particular file name is exists or not in the list.

Note: In the above code no need to provide the file name to the Url.

                        
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