是否有可能在PHP中覆盖函数 [英] Is it possible to overwrite a function in PHP

问题描述

您可以声明这样的函数...

pre $函数ihatefooexamples（）{
返回boo-foo！;
};

然后 redeclare 有点像这样...

  if（$ _GET ['foolevel'] == 10）{
 function ihatefooexamples（）{
 returnreally BOO-foo的; 
}; 
}; 
  

是否可以用这种方式覆盖函数？

$ b $ $ b

要解决评论，这个答案不直接解决
原来的问题。如果您是通过Google搜索获得的，请从这里开始

有一个可用的函数叫做 override_function ，它实际上符合法案。但是，鉴于此功能是高级PHP调试器扩展的一部分，这很难使 override_function（）用于生产使用的论点。因此，我会说不，不可能用原始提问者的想法覆盖函数。

原始答案

这是您应该利用OOP，特别是多态性的优势。

  interface Fooable 
 {
 public function ihatefooexamples（）; 
 
 
 class Foo implements Fooable 
 {
 public function ihatefooexamples（）
 {
 returnboo-foo！; 
 
 
 
 class FooBar implements Fooable 
 {
 public function ihatefooexamples（）
 {
 returnreally boo-富; 
} 
} 
 
 $ foo = new Foo（）; 
 
 if（10 == $ _GET ['foolevel']）{
 $ foo = new FooBar（）; 
} 
 
 echo $ foo-> ihatefooexamples（）; 
  

Can you declare a function like this...

function ihatefooexamples(){
  return "boo-foo!";
};

And then redeclare it somewhat like this...

if ($_GET['foolevel'] == 10){
  function ihatefooexamples(){
    return "really boo-foo";
  };
};

Is it possible to overwrite a function that way?

Any way?

解决方案

Edit

To address comments that this answer doesn't directly address the original question. If you got here from a Google Search, start here

There is a function available called override_function that actually fits the bill. However, given that this function is part of The Advanced PHP Debugger extension, it's hard to make an argument that override_function() is intended for production use. Therefore, I would say "No", it is not possible to overwrite a function with the intent that the original questioner had in mind.

Original Answer

This is where you should take advantage of OOP, specifically polymorphism.

interface Fooable
{
    public function ihatefooexamples();
}

class Foo implements Fooable
{
    public function ihatefooexamples()
    {
        return "boo-foo!";
    }
}

class FooBar implements Fooable
{
    public function ihatefooexamples()
    {
        return "really boo-foo";
    }
}

$foo = new Foo();

if (10 == $_GET['foolevel']) {
    $foo = new FooBar();
}

echo $foo->ihatefooexamples();

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