在Java 7中，Regex-replace-with-function-evaluation等价于什么？ [英] What is the equivalent of Regex-replace-with-function-evaluation in Java 7?

问题描述

我正在寻找一种非常简单的方法来获得与以下JavaScript代码类似的东西。也就是说，对于每场比赛，我想调用某个转换函数并将结果用作重置值。

  var res =Hello World！。replace（/ \ S + /，function（word）{
 //由于这个函数表示一个转换，
 //替换文字字符串（与replaceAll一样）不是可行的解决方案。
 return+ word.length; 
}）
 // res => 5 6
  

只有..在Java中。并且，最好作为可以重复使用的单一方法或模板。 解决方案

你的答案在 Matcher＃appendReplacement 文档。只需将你的函数调用放在while循环中即可。

[appendReplacement方法]旨在与appendTail一起用于循环，找到方法。例如，下面的代码在标准输出流中写入一条狗两只狗：

  Pattern p = Pattern.compile（cat）; 
 Matcher m = p.matcher（院内一只猫两只猫）; 
 StringBuffer sb = new StringBuffer（）; 
 while（m.find（））{
 m.appendReplacement（sb，dog）; 
} 
 m.appendTail（sb）; 
 System.out.println（sb.toString（））; 
  

I'm looking for a very simple way of getting the equivalent of something like the following JavaScript code. That is, for each match I would like to call a certain transformation function and use the result as the replacement value.

var res = "Hello World!".replace(/\S+/, function (word) {
    // Since this function represents a transformation,
    // replacing literal strings (as with replaceAll) are not a viable solution.
    return "" + word.length;
})
// res => "5 6"

Only .. in Java. And, preferably as a "single method" or "template" that can be reused.

解决方案

Your answer is in the Matcher#appendReplacement documentation. Just put your function call in the while loop.

[The appendReplacement method] is intended to be used in a loop together with the appendTail and find methods. The following code, for example, writes one dog two dogs in the yard to the standard-output stream:

Pattern p = Pattern.compile("cat");
Matcher m = p.matcher("one cat two cats in the yard");
StringBuffer sb = new StringBuffer();
while (m.find()) {
    m.appendReplacement(sb, "dog");
}
m.appendTail(sb);
System.out.println(sb.toString());

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