python 3.2如何在函数之间传递变量中的数据 [英] python 3.2 how to pass data in variables between functions
问题描述
我如何存储并将主内容从r转换为r?如果我使r =固定,它会打印r,但是如何将可变内容传递并保存到r中。我尝试了random.getstate / setstate,但它说函数对象不可下载。
从随机导入randrange
导入随机
def main():
r = random.randrange(1,13,1)
print(r)
r = random.randrange(1,13,1)
def two():
if r == 7或r == 11:
print(r)
else:
print(r)
main()
two()
那么,根据具体情况,您可能想要创建一个类或返回数据,然后将其作为参数传递,后者可能是您想要的代码,例如:
def main():
...
r = do_something()
...
return r
def two(r):
...
do_something_else(r)
...
r = main()
two(r)
如果这发生在您可以定义为实体的东西内,在类中做:
class Main():
def main(s elf):
...
self.r = do_something()
...
def two(self):
...
do_something_else(self.r)
...
main = Main()
main.main()
main.two()
然而,在这种情况下,这是不必要的,因为您正在创建一个没有真正封装任何内容的类。
How would I store and pass the contents of r from main into two? It will print r if I make it r = something fixed, but how do I pass and hold variable contents into r. I tried random.getstate/setstate but it was saying "function object not subscriptable".
import random
from random import randrange
def main():
r = random.randrange(1,13,1)
print (r)
r = random.randrange(1,13,1)
def two():
if r==7 or r==11:
print (r)
else:
print (r)
main()
two()
Well, depending on the situation, you either want to make a class or return the data, then pass it in as an argument, the latter is probably what you want given your code, so, for example:
def main():
...
r = do_something()
...
return r
def two(r):
...
do_something_else(r)
...
r = main()
two(r)
If this was happening within something you could define as an entity, you could do it in a class:
class Main():
def main(self):
...
self.r = do_something()
...
def two(self):
...
do_something_else(self.r)
...
main = Main()
main.main()
main.two()
However, in this case, this is unnecessary as you are creating a class that doesn't really encapsulate anything.
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