如何在JavaScript中传递和调用函数作为参数？ [英] How to pass and call a function as an argument in Javascript?

问题描述

我正在寻找将匿名函数传递给另一个函数，但它似乎没有按照我的意愿工作。

I'm looking to pass an anonymous function to another function, but it doesn't seem to be working as I'd like.

我已附加代码，我认为它会给你一个更好的想法，我会做什么。

I've attached the code, I think it'd give you a better idea what I'd to do.

如何成功地将函数作为参数传递，然后调用它？

How do I successfully pass a function as an argument, and then invoke it?

<script language="javascript" type="text/javascript">
function do_work(success) {
    success;
}

do_work(function () {
    alert("hello")
});

</script>

推荐答案

您必须实际调用函数：

function do_work(success) {
    success();
}

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