为什么当我将太多参数传递给函数时，PHP不会抛出错误？ [英] Why does PHP not throw an error when I pass too many parameters to a function?

问题描述

我是php的n00b。

 函数doFoo（$ name =johnny）{
回显Hello $ name。 < br />; 
} 
  

我拨打了这些电话

  doFoo（）; 
 doFoo（ted）; 
 doFoo（ted，22）; 
  

前两个输出了预期的结果，即

 您好johnny 
您好特德
  

但是第三次电话还打印了

 您好特权
  

我希望有一个错误，毕竟函数是为一个参数创建的，而我用两个参数调用它。

为什么没有错误？

解决方案

PHP不会在函数过载中引发错误。

I am a n00b at php. I was learning about Default Parameters so I made this function.

function doFoo($name = "johnny"){
    echo "Hello $name" . "<br />";
}

I made these calls

doFoo();  
doFoo("ted");  
doFoo("ted", 22); 

The first two printed what was expected i.e

Hello johnny  
Hello ted

but the third call also printed

Hello ted 

I was expecting an error, after all the function is made for one argument whereas I am calling it with two arguments.
Why was there no error?

解决方案

PHP doesn't throw an error on function overload.

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