值不被复制到下一个（本地）环境？ [英] values not being copied to the next (local) environment?

问题描述

考虑位于 calcDistance 内的 browser（）的输出：

Called from: calcDistance(object = rst, xy = xy[[i]][j, ], effect.distance = effect.distance)
Browse[1]> ls.str()
effect.distance :  num 236
object : Formal class 'RasterLayer' [package "raster"] with 12 slots
xy :  Named num [1:2] -101.8 35.5

Browse[1]> 
debugging in: xyValues(object = object, xy = xy, buffer = effect.distance)
debug: standardGeneric("xyValues")

Browse[2]> ls.str()
object : Formal class 'RasterLayer' [package "raster"] with 12 slots
xy :  Named num [1:2] -101.8 35.5

函数如下：simulationRun> createDistRaster> calcDistance> raster :: xyValues。在上面的输出中，你只能看到最后两个。 xyValues 来自栅格包。

Functions are as follows: simulationRun > createDistRaster > calcDistance > raster::xyValues. In the above output, you only see the last two. xyValues is from raster package.

第一段代码显示有三个对象： effect.distance ， object ， xy 。
在第二段中，我们通过调用debug（xyValues）来进入xyValues。
在第三段中我们可以看到缺少 effect.distance 。

First paragraph of code shows that three objects are present: effect.distance, object, xy. In second paragraph, we descend into xyValues by calling debug(xyValues). In third paragraph we can see that effect.distance is missing.

我的问题是：Even尽管 object 和 xy 似乎被复制到 xyValues 环境就好了， effect.distance 不是。

My question is: Even though object and xy seem to be copied to the xyValues environment just fine, effect.distance is not. How could this be explained?

我的sessionInfo（）

My sessionInfo()

R version 2.11.1 (2010-05-31) 
i386-pc-mingw32 

locale:
[1] LC_COLLATE=Slovenian_Slovenia.1250  LC_CTYPE=Slovenian_Slovenia.1250   
[3] LC_MONETARY=Slovenian_Slovenia.1250 LC_NUMERIC=C                       
[5] LC_TIME=Slovenian_Slovenia.1250    

attached base packages:
[1] splines   stats     graphics  grDevices utils     datasets  methods  
[8] base     

other attached packages:
 [1] raster_1.3-11   foreach_1.3.0   codetools_0.2-2 iterators_1.0.3
 [5] Hmisc_3.8-2     survival_2.35-8 spam_0.22-0     splancs_2.01-27
 [9] sp_0.9-66       spatstat_1.20-2 deldir_0.0-12   mgcv_1.6-2     

loaded via a namespace (and not attached):
[1] cluster_1.12.3     grid_2.11.1        lattice_0.18-8     Matrix_0.999375-39
[5] nlme_3.1-96        tools_2.11.1 

推荐答案

UPDATE：
在R邮件列表中也讨论了这个问题，结果在特定情况下解决传递参数时存在缺陷/不一致。这被报告给R.讨论可以在以下网址找到：
Nabble

非常有趣的问题。当您检查

Quite an interesting problem. When you check

showMethods("xyValues",incl=T)

有两个重要的代码块。具有xy的签名向量和xy作为矩阵的一个。由于你的对象是一个RasterLayer对象，你需要确保origin.point是一个矩阵。如果我们看代码，这实际上是违反直觉的。

There are two important chunks of code. The one with signature vector for xy, and one for xy as a matrix. As your object is a "RasterLayer" object, you need to make sure origin.point is a matrix. This is pretty counterintuitive actually if we look at the code

object="Raster", xy="vector"
function (object, xy, ...) 
{
    if (length(xy) == 2) {
        callGeneric(object, matrix(xy, ncol = 2), ...)
    }
    else {
        stop("xy coordinates should be a two-column matrix or data.frame, or a vector of two numbers.")
    }
}

所以这实际上只会将xy参数转换为矩阵，并将所有其他参数传递给下一个通用。下一个必须是这个：

So this actually only transforms the xy argument to a matrix, and passes all other arguments to the next generic. The next one has to be this one then :

object="RasterLayer", xy="matrix"
function (object, xy, ...) 
{
    .local <- function (object, xy, method = "simple", buffer = NULL, 
        fun = NULL, na.rm = TRUE) 
    {
        if (dim(xy)[2] != 2) {
            stop("xy has wrong dimensions; it should have 2 columns")
        }
        if (!is.null(buffer)) {
            return(.xyvBuf(object, xy, buffer, fun, na.rm = na.rm))
        }
        if (method == "bilinear") {
            return(.bilinearValue(object, xy))
        }
        else if (method == "simple") {
            cells <- cellFromXY(object, xy)
            return(.readCells(object, cells))
        }
        else {
            stop("invalid method argument. Should be simple or bilinear.")
        }
    }
    .local(object, xy, ...)
}

这一个采用参数缓冲区。为什么参数值无法在分析树中找到，我不知道，但是可以尝试通过给出矩阵作为输入而不是向量来避免方法级联。

This one takes the argument "buffer". Why the value for the argument can't be found in the parse tree, I have no clue, but you could try to avoid the method cascade by giving a matrix as input instead of a vector.

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