从javascript函数打开一个php页面 [英] Open a php page from javascript function

问题描述

我有一个php页面，first.php，我想通过从javascript函数传递一些参数来打开页面。请帮助我，谢谢。

  function（）{
 var tableName =<？= $ p ？>中; //从另一个php文件获取值
 var checkB = checkbox_form.checkbux [counter] .value; 
 window.open（'http：//localhost/first.php？q =+ checkB +& p =+ tableName'，'_self'）; 
} 
  

但我无法打开页面，请帮忙。在前面的回答中，你可以很容易地使用 window.location code>打开一个PHP页面;但是，当使用 encodeURIComponent（） JavaScript函数时，您应该始终记住在URL中使用它们时转义您的变量：

  window.location =http：//localhost/first.php？q =+ encodeURIComponent（checkB）+& p =+ encodeURIComponent（tableName）; 
  

I have a php page, first.php and I want to open the page with passing some arguments from a javascript function. Could you please help me, thanks.

function() {
    var tableName = "<?= $p ?>"; //obtaining the value from another php file
    var checkB = checkbox_form.checkbux[counter].value;
    window.open('"http://localhost/first.php?q="+checkB+"&p="+tableName', '_self');
}

But I am not able to open the page, please help. Thanks in advance.

解决方案

As the previous answers state, you could easily use window.location to open a PHP page; however, you should always remember to escape your variables when using them in a URL, using the encodeURIComponent() JavaScript function:

window.location = "http://localhost/first.php?q=" + encodeURIComponent(checkB) + "&p=" + encodeURIComponent(tableName);

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