在python中调用一个函数,得到'(函数)没有定义'? [英] Call a function in python, getting '(function) is not defined'?
问题描述
$ b
...
workout = input( )
如果锻炼==y:
ballone()
elif锻炼==n:
print(好吧。)
sys.exit(如果你赢了,就不用了)
else:
sys.exit(Could not understand)
# #Ball one
def ballone():
...
问题正在呼叫'ballone'。你可以看到它在被命令行(ballone())调用时被定义和完美工作。
任何想法?我已经在网上搜索,但似乎找不到任何东西来帮助我。如果还有其他代码需要发布,请告诉我们:)
将函数定义移动到之前
def ballone():
#...
if workout ==y:
ballone()
elif workout ==n:
print(Okay。)
sys.exit(Not如果你赢了)
else:
sys.exit(Could not understand)
函数存储在标识符(变量)中,就像您的锻炼
值一样。如果你没有先定义它,Python是如何知道它会在以后定义的?
I recently started learning Python and have some code here.
...
workout = input("Work out if you won?")
if workout == "y":
ballone()
elif workout == "n":
print("Okay.")
sys.exit("Not working out if you won")
else:
sys.exit("Could not understand")
##Ball one
def ballone():
...
The issue is calling 'ballone'. You can see that it is defined and works perfectly when called from the command line (ballone())
Any ideas? I have scoured the net but cannot seem to find anything to help me. If any more code needs posting then please let me know :)
Move the function definition to before the lines that use it.
def ballone():
# ...
if workout == "y":
ballone()
elif workout == "n":
print("Okay.")
sys.exit("Not working out if you won")
else:
sys.exit("Could not understand")
Functions are stored in identifiers (variables), just like your workout
value. If you don't define it first, how is Python to know it'll be defined later?
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