通过字典访问功能 [英] Access Functions via Dictionary

问题描述

我有这样的功能：

  def abc（a，b）：
 return a + b 
  

我想将它分配到这样的字典中：

  functions = {'abc'：abc（a，b）} 
  

问题在于，将它分配给字典时，由于参数尚未定义，所以我收到错误消息：

  NameError：名称'a'未定义
  

我会做显而易见的事情并提前定义参数，但我需要在一个循环中定义它们（然后根据定位它在列表中调用该函数），如下所示：

  functions_to_call = ['abc'] 
 for function_to_call：
a = 3 
b = 4 
＃这应该是定位并运行函数该字典是否在函数列表中。 
 if f函数：
函数[f] 
  

解决方案

$ b $

我需要在一个循环中定义它们（然后根据定位它在列表中调用该函数） b

然后，简单地将函数对象保存在字典中有什么问题：

  functions = {' abc'：abc} 
  

和然后应用一个和 b 给函数while循环：

 <$ c 
 $ b $ 3,4 
如果函数中有f：
函数[f]（a，b） ）
  

I have a function like this:

def abc(a,b):
    return a+b

And I want to assign it to a dictionary like this:

functions = {'abc': abc(a,b)}

The trouble is, when assigning it to the dictionary, since the arguments are not yet defined, I get the error:

NameError: name 'a' is not defined

I would do the obvious thing and define the arguments ahead of time but I need to define them in a loop (and then call the function based on locating it in a list) like this:

functions_to_call = ['abc']
for f in functions_to_call:
    a=3
    b=4
#This is supposed to locate and run the function from the dictionary if it is in the list of functions.
    if f in functions:
       functions[f] 

解决方案

I need to define them in a loop (and then call the function based on locating it in a list)

Then what's the issue with simply saving the function object in the dictionary:

functions = {'abc':abc}

and then applying a and b to the function while looping:

functions_to_call = ['abc']
for f in functions_to_call:
    a, b = 3, 4
    if f in functions:
       functions[f](a, b)

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