按照另一个数组快速排序数组 [英] sort a array according to another array, swift

问题描述

我想知道是否有任何内置函数可以根据另一个数组对数组进行排序。例如：根据testIntArray排序testStringArray

var testStringArray = [a，b，c，d， e]
var testIntArray = [21，3，43，5，1]

函数之后，testStringArray将

  testIntArray.sort // [1,3,5,21,43] 
 testStringArray // [e ，b，d，a，c] 
  

解决方案

  var array1 = [a，b，c，d，e] 
 var array2 = [21， 3，43，5，1] 
 
 let sorted = zip（array1，array2）.sort {$ 0.1< $ 1.1 
 $ b $ array1 = sorted.map {$ 0.0} 
 array2 = sorted.map {$ 0.1} 
 
 print（array1）// [e， b，d，a，c] 
 print（array2）// [1,3,5,21,43] 
  

类似这样的事情？我觉得它可以做得更好...

编辑：

这并不觉得它是好得多......

  zip（array1，array2）.sort {$ 0.1 < （$ 0.0，atIndex：array1.count）
 
 array2.removeAtIndex（array2）$ for $ {
 array1.removeAtIndex .indexOf（$ 0.1）！）
 array2.insert（$ 0.1，atIndex：array2.count）
} 
 
 print（array1）// [e，b ，d，a，c] 
 print（array2）// [1,3,5,21,43] 
  

I am wondering is there any build-in function I can sort a array according to another array. For example: sort testStringArray according to testIntArray

var testStringArray = ["a", "b", "c", "d", "e"] var testIntArray = [21, 3, 43, 5, 1]

After the function, testStringArray will be

testIntArray.sort // [1, 3, 5, 21, 43]
testStringArray // ["e", "b", "d", "a", "c"]

解决方案

var array1 = ["a", "b", "c", "d", "e"]
var array2 = [21, 3, 43, 5, 1]

let sorted = zip(array1, array2).sort { $0.1 < $1.1 }

array1 = sorted.map { $0.0 }
array2 = sorted.map { $0.1 }

print(array1) // ["e", "b", "d", "a", "c"]
print(array2) // [1, 3, 5, 21, 43]

Something like this? I feel like it can be done better...

EDIT:

This doesn't feel like it's much better...

zip(array1, array2).sort { $0.1 < $1.1 }.forEach {
    array1.removeAtIndex(array1.indexOf($0.0)!)
    array1.insert($0.0, atIndex: array1.count)

    array2.removeAtIndex(array2.indexOf($0.1)!)
    array2.insert($0.1, atIndex: array2.count)
}

print(array1) // ["e", "b", "d", "a", "c"]
print(array2) // [1, 3, 5, 21, 43]

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