功能和分离程序 [英] Functions and separating a program

问题描述

基本上，我这周的作业是：

写出三个函数：
一个当提供两个整数时，返回下一个。
另一个返回两个整数的较高者。
第三个返回提供的两个整数的平均值
为了测试你的函数，编写一个提示两个整数的程序，然后
打印出较低的值，然后再打印出较高的值，然后再平均值。
您的程序应该包含函数原型。

无论如何，正如我之前提到的，尽管这是我最喜欢的模块。

所以这里是我的代码到目前为止（令人尴尬）。我无法弄清楚，如果我的逻辑应该高于或低于整数的主线。整体上真的很混乱。我一直在努力研究这个模块（远远超过所有其他模块），但仍然觉得它是一个迷失的孩子。

  #include< stdio.h> 
 #include< stdlib.h> 
 
 int getLow（int num1 int num2）; 
 
 int getHigh（int num1 int num2）; 
 
 int getAvg（int num1 int num2）; 
 
 int main（）
 {
 int lores，hires，avres; 
 
 
 printf（输入两个整数：\\\
）; 
 scanf（％i％i，& num1，& num2）; 
 $ b int getLow（int num1，int num2）{
 
 if（num1  printf（％i是最低的\ n ，num1）;} 
 if（num1> num2）{
 printf（％i is the lowest \\\
，num2）;}} 
 
 int getLow（ int num1，int num2）{
 
 if（num1> num2）{
 printf（％i是最高的\ n，num1）;} 
 if（ num1  printf（％i是最高的\ n，num2）;}} 
 
 int getAvg（int num1，int num2）
 
 getAvg =（num1 + num2）/ 2; 
 
 printf（％i是两个整数的平均数\\\
，getAvg）; 
 
返回0; 
} 
  

解决方案

  #include< stdio.h> 
 #include< stdlib.h> 
 
 int getLow（int num1，int num2）; 
 int getHigh（int num1，int num2）; 
 float getAvg（int num1，int num2）; 
 
 int main（）
 {
 int num1，num2，avres; 
 
 printf（输入两个整数：\\\
）; 
 scanf（％i％i，& num1，& num2）; 
 
 float avg = getAvg（num1，num2）; 
 printf（最小的数字是％d，getLow（num1，num2））; 
 printf（最大的数字是％d，getHigh（num1，num2））; 
 printf（％f是两个整数的平均数\ n，avg）; 
 
返回0; 
 
 
 $ b float getAvg（int num1，int num2）
 {
 return（num1 + num2）/ 2 .; 
 
 $ b $ int getLow（int num1，int num2）
 {
 if（num1  {
 return num1; 
} 
 else 
 {
 return num2; 
} 
} 
 
 int getHigh（int num1，int num2）
 {
 if（num1> num2）
 {
返回num1; 
} 
 else 
 {
 return num2; 
} 
 
} 
  

Basically my homework this week is:

Write three functions: One which when supplied with two integers, returns the lower. Another which returns the higher of two supplied integers. And a third which returns the average of two supplied integers To test your functions, write a program which prompts for two integers and then prints out the lower, then the higher and then the average. Your program should include the function prototypes.

Anyway, as I mentioned before, I seem to have real difficulty with this module - even though it is my favourite.

So here is my code so far (embarrassing). I cant work out if my logic should be above or below the int main line. Just really confused overall. I have been trying so hard with this module (far more than all of the others) but still feel like a lost child with it.

#include <stdio.h>
#include <stdlib.h>

int getLow(int num1 int num2);

int getHigh(int num1 int num2);

int getAvg(int num1 int num2);

int main()
{
    int lores, hires, avres;


    printf("Enter two integers:\n");
    scanf("%i %i", &num1, &num2);

    int getLow(int num1, int num2){

    if (num1 < num2){
        printf("%i is the lowest\n", num1);}
      if (num1 > num2){
        printf("%i is the lowest\n", num2);}}

   int getLow(int num1, int num2){

    if (num1 > num2){
        printf("%i is the highest\n", num1);}
      if (num1 < num2){
        printf("%i is the highest\n", num2);}}

    int getAvg(int num1, int num2)

    getAvg = (num1 + num2) / 2;

     printf("%i is the average of the two integers\n", getAvg);

    return 0;
}

解决方案

#include <stdio.h>
#include <stdlib.h>

int getLow(int num1, int num2);
int getHigh(int num1, int num2);
float getAvg(int num1, int num2);

int main()
{
    int num1, num2, avres;

    printf("Enter two integers:\n");
    scanf("%i %i", &num1, &num2);

    float avg = getAvg(num1, num2);
    printf("The smallest number is %d", getLow(num1, num2));
    printf("The largest number is %d", getHigh(num1, num2));
    printf("%f is the average of the two integers\n", avg);

    return 0;

}

float getAvg(int num1, int num2)
{
    return (num1 + num2) / 2.;
}

int getLow(int num1, int num2)
{
    if (num1 < num2)
    {
        return num1;
    }
    else
    {
        return num2;
    }
}

int getHigh(int num1, int num2)
{
    if (num1 > num2)
    {
        return num1;
    }
    else
    {
        return num2;
    }

}

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