转换匿名函数的输入 [英] Convert input of an anonymous function

问题描述

我有一个带有两个参数的匿名函数 A 。我需要转换这个函数，所以它需要一个参数，通过改变另一个参数为一个常量。

例如有一个函数：
A = @（X，Y）X + Y;
我想现在有：
B = @（Y）3 + Y;

这在数学中似乎是正常的事情，所以我猜想有一种方法可以在MATLAB中做这样的事情。虽然我找不到解决方案。

我需要这样做的原因是我有一个函数对 A ，但当 A 的参数之一是常量时，还需要解决问题。例如，为 X = 3 找到 A 的最小值。

X 设置为 3 中，但如果你想创建另一个匿名函数，这里是如何做到这一点：

  A = @（X ，Y）X + Y; 
 B = @（Y）A（3，Y）; ％在这里你已经把X = 3 
  

验证：

 >> A（3,4）
 
 ans = 
 
 7 
 
>> B（4）
 
 ans = 
 
 7 
  

I have an anonymous function A taking two arguments. I need to convert this function so it takes one argument, by changing the other argument to a constant.

For example having a function: A = @(X, Y) X + Y; I would like now to have: B = @(Y) 3 + Y;

This seems to be a normal thing to do in mathematics, so I guess there is a way to do such thing in MATLAB. I cannot find the solution though.

The reason I need to do something like this is that I have a function that does some calculations on A, but also needs to solve problems when one of the A's arguments is constant. For example find a minimum of the A for X = 3.

解决方案

You can use the same anonymous function and put X as 3 in it but if you want to create another anonymous function, here is how to do that:

A = @(X, Y) X + Y;   
B = @(Y) A(3,Y);     %Here you have put X=3

To verify:

>> A(3,4)

ans =

     7

>> B(4)

ans =

     7

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