如何在Oracle函数中返回动态结果集 [英] how to return a dynamic result set in Oracle function
本文介绍了如何在Oracle函数中返回动态结果集的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我在网上找到了一个字符串标记器查询,并将其打包到下面的函数中,该函数返回动态的标记集。该函数编译成功,但不知何故我得到错误ORA-00933:SQL命令未正确结束。有人可以帮我调试吗?谢谢。
CREATE OR REPLACE TYPE KEY_VALUE_TYPE is object(k varchar2(4000),v varchar2(4000));
CREATE OR REPLACE TYPE KEY_VALUE_TABLE是key_value_type的表;
创建或替换函数StrTokenizer
(字符串IN VARCHAR2,分隔符IN VARCHAR2)
RETURN key_value_table AS
v_ret key_value_table;
BEGIN
SELECT
CAST(
multiset(
SELECT
LEVEL k,
SUBSTR(STRING_TO_TOKENIZE,
DECODE(LEVEL, 1,1,INSTR(STRING_TO_TOKENIZE,DELIMITER,1,LEVEL-1)+1),
INSTR(STRING_TO_TOKENIZE,DELIMITER,1,LEVEL)
- DECODE(LEVEL,1,1,INSTR(STRING_TO_TOKENIZE ,DELIMITER,1,LEVEL-1)+1))v
FROM
(
SELECT
':string'||':delimiter'AS STRING_TO_TOKENIZE,':delimiter' AS DELIMITER
FROM
DUAL
)
CONNECT BY INSTR(STRING_TO_ENKENIZE,DELIMITER,1,LEVEL)> 0
ORDER BY level ASC)
As key_value_table)
INTO
v_ret
FROM dual;
return v_ret;
END;
select * from strtokenizer('a,b,c',',')
ORA-00933:SQL命令未正确结束
编辑:
-
select * from table(strtokenizer('a,b,c',','))
给出了ORA-30732:表不包含用户可见的列。当我作为函数所有者登录时,ORA-30732
不见了,但函数不能用传递的值替换
':string'||':delimiter'值。我该如何解决这个问题?当我没有作为它的所有者登录时,如何运行一个函数?
解决方案
假设函数编译,请尝试:
SELECT *
FROM TABLE(strtokenizer('a,b,c',','));
参考:
该功能需要更正 - 使用:
$ pre $ CREATE OR REPLACE FUNCTION StrTokenizer(字符串IN VARCHAR2,
delimiter IN VARCHAR2)
RETURN key_value_table AS v_ret key_value_table
BEGIN
SELECT CAST(MULTISET(SELECT LEVEL k,
SUBSTR(STRING_TO_TOKENIZE,DECODE(LEVEL,1,1,INSTR(STRING_TO_TOKENIZE,DELIMITER,1,LEVEL-1)+1),
INSTR(STRING_TO_TOKENIZE,DELIMITER,1,LEVEL) - DECODE(LEVEL,1,1,INSTR(STRING_TO_TOKENIZE,DELIMITER,1,LEVEL-1)+1))v
FROM(SELECT string || delimiter AS STRING_TO_TOKENIZE ,
分隔符AS DELIMITER
FROM DUAL)
CONNECT BY INSTR(STRING_TO_KENIZE,DELIMITER,1,LEVEL)> 0
ORDER BY level ASC)AS key_value_table)
INTO v_ret
FROM DUAL;
RETURN v_ret;
END;
I found a string tokenizer query on the net and packaged it into the below function, which return the dynamic set of tokens. The function compiles successfully but somehow I get the error "ORA-00933: SQL command not properly ended". Can someone please help me debug this? Thank you.
CREATE OR REPLACE TYPE KEY_VALUE_TYPE is object (k varchar2(4000), v varchar2(4000));
CREATE OR REPLACE TYPE KEY_VALUE_TABLE is table of key_value_type;
CREATE OR REPLACE FUNCTION StrTokenizer
(string IN VARCHAR2, delimiter IN VARCHAR2)
RETURN key_value_table AS
v_ret key_value_table;
BEGIN
SELECT
CAST(
multiset(
SELECT
LEVEL k,
SUBSTR(STRING_TO_TOKENIZE,
DECODE(LEVEL, 1, 1, INSTR(STRING_TO_TOKENIZE, DELIMITER, 1, LEVEL-1)+1),
INSTR(STRING_TO_TOKENIZE, DELIMITER, 1, LEVEL)
- DECODE( LEVEL, 1, 1, INSTR(STRING_TO_TOKENIZE, DELIMITER, 1, LEVEL-1)+1)) v
FROM
(
SELECT
':string'||':delimiter' AS STRING_TO_TOKENIZE , ':delimiter' AS DELIMITER
FROM
DUAL
)
CONNECT BY INSTR(STRING_TO_TOKENIZE, DELIMITER, 1, LEVEL)>0
ORDER BY level ASC)
As key_value_table)
INTO
v_ret
FROM dual;
return v_ret;
END;
select * from strtokenizer('a,b,c',',')
ORA-00933: SQL command not properly ended
Edit:
select * from table(strtokenizer('a,b,c',','))
gives "ORA-30732: table contains no user-visible columns".ORA-30732
is gone when I logged on as the function owner, but the function cannot replace ':string'||':delimiter' with the passed-in values. How can I correct this? And how can I run a function when I am not logged on as its owner? Thank you.
解决方案
Assuming the function compiles, try:
SELECT *
FROM TABLE(strtokenizer('a,b,c',','));
Reference:
The function needs to be corrected - use:
CREATE OR REPLACE FUNCTION StrTokenizer (string IN VARCHAR2,
delimiter IN VARCHAR2)
RETURN key_value_table AS v_ret key_value_table
BEGIN
SELECT CAST(MULTISET(SELECT LEVEL k,
SUBSTR(STRING_TO_TOKENIZE, DECODE(LEVEL, 1, 1, INSTR(STRING_TO_TOKENIZE, DELIMITER, 1, LEVEL-1)+1),
INSTR(STRING_TO_TOKENIZE, DELIMITER, 1, LEVEL) - DECODE( LEVEL, 1, 1, INSTR(STRING_TO_TOKENIZE, DELIMITER, 1, LEVEL-1)+1)) v
FROM (SELECT string || delimiter AS STRING_TO_TOKENIZE ,
delimiter AS DELIMITER
FROM DUAL)
CONNECT BY INSTR(STRING_TO_TOKENIZE, DELIMITER, 1, LEVEL)>0
ORDER BY level ASC) AS key_value_table)
INTO v_ret
FROM DUAL;
RETURN v_ret;
END;
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