Cellfun与Structfun函数? [英] Cellfun with Structfun as function?
问题描述
fun =函数(foo,index1,index2)
cellfun(@structfun(@(x)x(index1:index2),foo,'UniformOutput',false ),foo,'UniformOutput',false)
我必须做一个循环并且替换第一个foo与foo(i)能够到达所有单元格?提前致谢。
不能像这样内联structfun。你需要创建一个调用structfun并在cellfun中使用它的临时函数句柄。
$ p $ s $ =(y)structfun(@(x)x(1:2),y,'UniformOutput',false );
cellfun(sf,foo,'UniformOutput',false);
您可以在一行中做到这一点,如下所示。但为了便于阅读,最好将它分成两行。
cellfun(@(y)structfun(@(x)x (1:2),y,'UniformOutput',false),foo,'UniformOutput',false);
My data are in the form of a cell array of structs. I am trying to implement a cellfun call that takes structfun as its function that, at the end of the day, will resize all of the vectors in the struct to the passed-in size. E.g. I have a 4-cell array each with a struct that contains one vector (going to be multiple vectors once I figure this out), and I want to resize each vector from index1 to index2
fun = function(foo, index1, index2)
cellfun(@structfun(@(x) x(index1:index2), foo, 'UniformOutput',false), foo, 'UniformOutput', false)
Do I have to do a loop and replace the first "foo" with "foo(i)" to be able to reach all the cells? Thanks in advance.
You cannot inline structfun like that. You need to create a temporary function handle which calls structfun and use that in cellfun.
sf = @(y) structfun(@(x) x(1:2), y, 'UniformOutput',false);
cellfun(sf, foo, 'UniformOutput', false);
You can do this in one line as below. But it is better to keep this in two lines for readability.
cellfun(@(y) structfun(@(x) x(1:2), y, 'UniformOutput',false), foo, 'UniformOutput', false);
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