找出实例变量名称本身 [英] Find out instance variable name out of itself

问题描述

  function MyClass（）{
 this.myProp =''; 
} 
 MyClass.prototype.myTestFunction = function（）{
 alert（'test'）; 
} 
  

现在，我们实例化这个类。

  var myTestInstance = new MyClass（）; 
 myTestInstance.myTestFunction（）; 
  

这会输出一个警报'test'。

现在我希望将变量名'myTestInstance'放入函数'myTestFunction（）'中，而不必将其作为参数传递。

是否有可能从被调用的函数中找出实例的变量名？

感谢您的帮助！

编辑：只是为了添加信息为什么我需要这个：我在我的真实项目中创建的每个实例都是一个特殊的HTML表格。在标题字段中是每列的排序按钮。因此，我动态地添加了一个链接元素 href ='javascript：myTableInstance.sort（）'。要在实例中动态地打印它，我需要变量名称。

会有另一个更好的解决方案吗？ h2_lin>解决方案

不，它没有任何意义。首先，实例不绑定到一个变量（它可能被很多变量引用，它可能被none引用 - 可能作为某个数组的成员） - 所以问题存储变量的名称是什么该实例无法回答。其次，myTestFunction和myTestInstance的范围可能会非常不同。在通常情况下，myTestFunction不会看到myTestInstance定义的范围 - 因此知道变量的名称将无济于事。

您应该只使用this在myTestFunction里面。

I've created a JavaScript Class just as following:

function MyClass() {
    this.myProp = '';
}
MyClass.prototype.myTestFunction = function() {
    alert('test');
}

Now, I instantiate this class.

var myTestInstance = new MyClass();
myTestInstance.myTestFunction();

This outputs an alert with 'test'.

Now I want to have the variable name 'myTestInstance' into the function 'myTestFunction()' without having to pass it as a parameter.

Is it somehow possible to find out the variable name of the instance from inside the called function?

Thank you for your help!

EDIT: Just to add information why I would need this: Every instance I create in my real project is a special HTML table. In the header fields are sort-buttons for every column. Therefore I added dynamically a link-element with href='javascript:myTableInstance.sort()'. To print this dynamically IN the instance, I needed the variable name.

Would there be another, better solution?

解决方案

No, it does not make sense in any way. First of all, instance is not tied to a single variable (it might be referenced by many variables, it could be referenced by none - perhaps as a member of some array) - so the question "what is the name of the variable that stores the instance" is unanswerable. Secondly, the scope of myTestFunction and myTestInstance could be very different. In a usual case myTestFunction would not "see" the scope that has myTestInstance defined - so knowing the name of the variable would not help.

You should just use "this" inside myTestFunction.

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