意外的T_ELSE [英] Unexpected T_ELSE

问题描述

我已经创建了一段代码，并且我已经'require_once'进入我的PHP代码很长一段时间了。它在我的本地PC上正常工作，但是当我将它上传到我的服务器时，它会出现以下错误：

 解析错误：语法错误，在第47行的/home/makequiz/public_html/nitpicker/func.php中出现意外的T_ELSE 
  

这是函数：

 函数howLongAgo（$ unix_time）{
 //此函数显示unix时间戳
 //作为秒数，分钟数，小时数，天数，月数，年前数
 
 
 //获取指定时间与当前unix时间之间的时间差
 $ time_difference = time（） -  $ unix_time; 
 
 $ seconds_ago = $ time_difference; 
 $ minutes_ago = $ time_difference / 60; 
 $ hours_ago = $ time_difference / 3600; 
 $ days_ago = $ time_difference / 86400; 
 $ months_ago = $ time_difference / 2629743; 
 $ years_ago = $ time_difference / 31556926; 
 $ b $如果（$ time_difference <60）{
 //秒前
返回一轮（$ time_difference）。 '秒以前'; $（b 
 $ b）else if（（$ time_difference> = 60）&&（$ time_difference <3600））{
 
 //分钟前
 if （$（$ time_difference / 60）== 1）{
 return round（$ time_difference / 60）。 一分钟前; 
} else {
 return round（$ time_difference / 60）。  几分钟前; 
} 
 
} else if（$ time_difference> = 3600&& $ time_difference< 86400）{
 //小时前
 if（round $ time_difference / 3600）== 1）{
 return round（$ time_difference / 3600）。  一个小时前; 
} else {
 return round（$ time_difference / 3600）。 小时前; 
} 
} else if（$ time_difference> = 86400&& $ time_difference< 2629743）{
 //天数
 if（round（$ time_difference / 86400 ）== 1）{
 return round（$ time_difference / 86400）。 天之前; 
} else {
 return round（$ time_difference / 86400）。  几天前; 
} 
} else if（$ time_difference> = 2629743&& $ time_difference< 31556926）{
 //月前
 if（round（$ time_difference / 2629743 ）== 1）{
 return round（$ time_difference / 2629743）。  一个月前; 
} else {
 return round（$ time_difference / 2629743）。  几个月前; 
} 
} else if（$ time_difference> = 31556926）{
 // Years Ago 
 if（round（$ time_difference / 31556926）== 1）{
返回（$ time_difference / 31556926）。  一年前; 
} else {
 return round（$ time_difference / 31556926）。  多年前; 
 
 
 
 code 
 $ b 
这个错误即将到来，即使我没有在我的代码中调用函数。
 
 
 
任何人都可以在代码中看到任何错误，因为我不能：（
解决方案
使用switch / case逻辑方案会更简单一些，我使用switch / case重新编写了那些代码，这可能是你学习switch / case的一个很好的介绍，你在上面的if语句中有一些额外的（），我希望这会有所帮助，朋友： 
 
 
< ;? 
 $ unix_time = 6734; 
 echo howLongAgo（$ unix_time）; 
 
函数howLongAgo（$ time_difference）{
 
 //基于传递给这个函数的时间差的Swtich逻辑，设置英文字符串和差值需要除以
 switch（$ time_difference）{
 case（$ time_difference <60）：
 $ string =second; 
 break; 
情况（$ time_difference> = 60&& $ time_difference< 3600）：
 $ string =minute; 
 $ divider = 60; 
休息; 
 case（$ time_difference> = 3600&& $ time_difference< 86400）：
 $ string =hour; 
 $ divider = 3600; 
休息; 
 case（$ time_difference> = 86400&& $ time_difference< 2629743）：
 $ string =day; 
 $ divider = 86400; 
休息; 
 case（$ time_difference> = 2629743&& $ time_difference< 31556926）：
 $ string =month; 
 $ divider = 2629743; 
休息; 
 case（$ time_difference> = 31556926）：
 $ string =year; 
 $ divider = 31556926; 
休息; 
 
 
 //如果在交换过程中设置了分隔符值，则使用它获取实际差异
如果（$ divider）{$ diff = round（$ time_difference /如果差异不等于1，则复制最终结果EG：小时，分钟，秒
 if（$ diff）;} else {$ diff = round（$ time_difference）;} 
 //如果！= 1）{$ pluralize =s;} 
 //连接所有变量并返回它们
 $ final = $ diff。 $字符串。 $ pluralize。 前; 
返回$ final; 
 
} 
？> 
  
 
I've got a piece of code that I created and I've been 'requiring_once' in to my PHP code for quite a while now.  It works fine on my local PC, but when I upload it to my server it's coming up with the following error: 
Parse error: syntax error, unexpected T_ELSE in /home/makequiz/public_html/nitpicker/func.php on line 47
Here's the function:
function howLongAgo($unix_time) {
// This function shows the unix time stamp 
// as number of seconds, minutes, hours, days, months, years ago 


// Get the time difference between time specified and the current unix time 
$time_difference = time () - $unix_time;

$seconds_ago = $time_difference;
$minutes_ago = $time_difference / 60;
$hours_ago = $time_difference / 3600;
$days_ago = $time_difference / 86400;
$months_ago = $time_difference / 2629743;
$years_ago = $time_difference / 31556926;

if ($time_difference < 60) {
    // Seconds Ago 
    return round ( $time_difference ) . ' Seconds Ago';

} else if ( ($time_difference >= 60) && ($time_difference < 3600) ) {

    // Minutes Ago
    if (round ( $time_difference / 60 ) == 1) {
        return round ( $time_difference / 60 ) . " Minute Ago";
    } else {
        return round ( $time_difference / 60 ) . " Minutes Ago";
    }

} else if ($time_difference >= 3600 && $time_difference < 86400) {
    // Hours Ago 
    if (round ( $time_difference / 3600 ) == 1) {
        return round ( $time_difference / 3600 ) . " Hour Ago";
    } else {
        return round ( $time_difference / 3600 ) . " Hours Ago";
    }
} else if ($time_difference >= 86400 && $time_difference < 2629743) {
    // Days Ago 
    if (round ( $time_difference / 86400 ) == 1) {
        return round ( $time_difference / 86400 ) . " Day Ago";
    } else {
        return round ( $time_difference / 86400 ) . " Days Ago";
    }
} else if ($time_difference >= 2629743 && $time_difference < 31556926) {
    // Months Ago 
    if (round ( $time_difference / 2629743 ) == 1) {
        return round ( $time_difference / 2629743 ) . " Month Ago";
    } else {
        return round ( $time_difference / 2629743 ) . " Months Ago";
    }
} else if ($time_difference >= 31556926) {
    // Years Ago 
    if (round ( $time_difference / 31556926 ) == 1) {
        return round ( $time_difference / 31556926 ) . " Year Ago";
    } else {
        return round ( $time_difference / 31556926 ) . " Years Ago";
    }
}
}
This error is coming up, even though I haven't called the function at all in my code.


Can anyone see any errors in the code, cause I can't :(
解决方案
This would be a lot simpler using a switch/case logic scheme. I have re-coded what you had up there using switch/case and this might be a good intro for you to learn switch/case. You had some extra ( ) in one of the if statements above. I hope this helps, friend:
<?
$unix_time = 6734;
echo howLongAgo($unix_time);

function howLongAgo($time_difference){

// Swtich logic based on the time difference passed to this function, sets the english string and what number the difference needs to be divided by
    switch($time_difference){
         case ($time_difference < 60):
              $string = " second";
              break;
         case ($time_difference >= 60 && $time_difference < 3600):
              $string = " minute";
              $divider = 60;
              break;
         case ($time_difference >= 3600 && $time_difference < 86400):
              $string = " hour";
              $divider = 3600;
              break;
         case ($time_difference >= 86400 && $time_difference < 2629743):
              $string = " day";
              $divider = 86400;
              break;
         case ($time_difference >= 2629743 && $time_difference < 31556926):
              $string = " month";
              $divider = 2629743;
              break;
         case ($time_difference >= 31556926):
              $string = " year";
              $divider = 31556926;
              break;
    }

// If a divider value is set during the switch, use it to get the actual difference
if($divider){$diff = round($time_difference / $divider);}else{$diff = round($time_difference);}
// If the difference does not equal 1, pluralize the final result EG: hours, minutes, seconds
if($diff != 1){$pluralize="s";}
// Concatenate all variables together and return them
$final =  $diff . $string . $pluralize . " ago";
return $final;

}
?>


                        
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