堆栈溢出从Java深层递归? [英] Stack overflows from deep recursion in Java?

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问题描述

在使用函数式语言的一些经验后,我开始在Java中更多地使用递归 - 但是这种语言似乎有一个相对较浅的调用堆栈,大约有1000个。



有没有办法让调用堆栈更大?像我可以让数百万通话深度的函数一样,比如Erlang?



当我执行Project Euler问题时,我越来越注意到这一点。



谢谢。

解决方案

我猜你可以使用这些参数。 b
$ b


-ss Stacksize增加本地
堆栈大小或



-oss Stacksize to增加Java
堆栈大小,

默认的本地堆栈大小为128k,
,最小值为1000字节。
默认的Java堆栈大小为400k,最小值为1000字节的


http://edocs.bea.com/wls/docs61/faq/java.html# 251197



编辑:

在阅读第一条评论(Chuck's)之后,当重读这个问题并阅读另一个答案时,我想澄清一下,我将问题解释为增加堆栈大小。我没有打算说你可以有无限的堆栈,比如在函数式编程中(一种编程范式,我只是在它的表面上划过)。


After some experience with functional languages, I'm starting to use recursion more in Java - But the language seems to have a relatively shallow call stack of about 1000.

Is there a way to make the call stack bigger? Like can I make functions that are millions of calls deep, like in Erlang?

I'm noticing this more and more when I do Project Euler problems.

Thanks.

解决方案

I guess you could use these parameters

-ss Stacksize to increase the native stack size or

-oss Stacksize to increase the Java stack size,

The default native stack size is 128k, with a minimum value of 1000 bytes. The default java stack size is 400k, with a minimum value of 1000 bytes.

http://edocs.bea.com/wls/docs61/faq/java.html#251197

EDIT:

After reading the first comment (Chuck´s), as well as re reading the question and reading another answers, i´d like to clarify that i interpreted the question as just "increase stack size". I didn´t intend to say that you can have infinite stacks, such as in functional programming (a programming paradigm which i´ve only scratched its surface).

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