为什么在foldLeft中留下点会导致编译错误？ [英] Why does leaving the dot out in foldLeft cause a compilation error?

问题描述

任何人都可以解释为什么我忽略用于应用 foldLeft 函数的点符号（版本2.9.2）时为什么会看到以下编译错误

Can anyone explain why I see this compile error for the following when I omit the dot notation for applying the foldLeft function?(version 2.9.2)

scala> val l = List(1, 2, 3)
res19: List[Int] = List(1 ,2 ,3)

scala> l foldLeft(1)(_ * _)
<console>:9: error: Int(1) does not take parameters
                    l foldLeft(1)(_ * _)
                                    ^

但是

but

scala> l.foldLeft(1)(_ * _) 
res27: Int = 6

不适用于其他高阶函数，如 map ，它似乎并不关心我是否提供点。

This doesn't hold true for other higher order functions such as map which doesn't seem to care whether I supply the dot or not.

我不认为它是一个关联事物，因为我不能只调用 foldLeft（1）

I don't think its an associativity thing because I can't just invoke foldLeft(1)

推荐答案

这是因为foldLeft是咖喱。除了使用点符号，还可以通过添加圆括号来解决此问题：

It's because foldLeft is curried. As well as using the dot notation, you can also fix this by adding parentheses:

scala> (l foldLeft 1)(_ * _)
res3: Int = 6

并且关于您对无法调用 foldLeft（l）的评论，您可以，但您需要像这样部分应用它：

Oh - and regarding your comment about not being able to invoke foldLeft(l), you can, but you need to partially apply it like this:

scala> (l foldLeft 1) _
res3: ((Int, Int) => Int) => Int = <function1>

这篇关于为什么在foldLeft中留下点会导致编译错误？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！