是否有一个从列表中生成元组的scala列表操作? [英] Is there a scala list operation that makes tuples from lists?
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问题描述
我正在尝试在列表中处理三元组。我必须这样做:
pre $
for(i = 1; i {
process(list [i-1],list [i],list [i + 1])$ b $ b}
在Scala中有一个List函数(或者如何编写它)可以做这样的事情:
val data = [1,2,3,4,5,6,7,8,9,10]
val tuples = data.some_magic_func
元组将会是[ (1,2,3),(2,3,4),(3,4,5),(4,5,6)...]
谢谢!
解决方案
val data = List(1,2,3,4,5,6,7,8,9,10)
val tuples = data.sliding(3).toList
//元组将会是List (列表(1,2,3),列表(2,3,4),列表(3,4,5),列表(4,5,6)...)
I'm trying to process triplets in a list. Imperatively, I could do this:
for(i = 1; i < list.length-1; i++)
{
process( list[i-1], list[i], list[i+1] )
}
Is there a List function in Scala (or how would one write it) that can do something like this:
val data = [1,2,3,4,5,6,7,8,9,10]
val tuples = data.some_magic_func
tuples would be[(1,2,3), (2,3,4), (3,4,5), (4,5,6) ... ]
Thanks!
解决方案
val data = List(1,2,3,4,5,6,7,8,9,10)
val tuples = data.sliding(3).toList
// tuples would be List(List(1,2,3), List(2,3,4), List(3,4,5), List(4,5,6) ... )
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