C#中的通用映射/减少列表扩展 [英] Generic Map/Reduce List Extensions in C#

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问题描述

  public delegate R ReduceFunction< T, R(T t,R前一个); 
public delegate void TransformFunction< T>(T t,params object [] args);

public static R Reduce< T,R>(这个List< T>列表,ReduceFunction< T,R> r,R initial)
{
var aggregate = initial;
foreach(列表中的变量)
aggregate = r(t,aggregate);

return aggregate;

public static void Transform< T>(this List< T> list,TransformFunction< T> f,params object [] args)
{
foreach列表)
f(t,args);

$ / code>

转换函数将减少cruft,如:

  foreach(列表中的变量)
if(条件&& moreconditions)
//执行工作等

这是否有意义?

解决方案

这些看起来与Linq中的扩展非常相似:

  //采用一个匹配Func< T,R>委托
listInstance.Aggregate(
startingValue,
(x,y)=> / *汇总两个后续值* /);

//使用一个匹配Action< T>委托
listInstance.ForEach(
x => / *用x * /做某事);

为什么第二个例子叫做Transform?你打算改变列表中的值吗?如果是这种情况,您最好使用 ConvertAll< T> 选择< T>


I am writing a few extensions to mimic the map and reduce functions in Lisp.

public delegate R ReduceFunction<T,R>(T t, R previous);
public delegate void TransformFunction<T>(T t, params object[] args);

public static R Reduce<T,R>(this List<T> list, ReduceFunction<T,R> r, R initial)
{
     var aggregate = initial;
     foreach(var t in list)
         aggregate = r(t,aggregate);

     return aggregate;
}
public static void Transform<T>(this List<T> list, TransformFunction<T> f, params object [] args)
{
    foreach(var t in list)
         f(t,args);
}

The transform function will cut down on cruft like:

foreach(var t in list)
    if(conditions && moreconditions)
        //do work etc

Does this make sense? Could it be better?

解决方案

These look very similar to extensions in Linq already:

//takes a function that matches the Func<T,R> delegate
listInstance.Aggregate( 
    startingValue, 
    (x, y) => /* aggregate two subsequent values */ );

//takes a function that matches the Action<T> delegate
listInstance.ForEach( 
    x => /* do something with x */);

Why is the 2nd example called Transform? Do you intend to change the values in the list somehow? If that's the case you may be better off using ConvertAll<T> or Select<T>.

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