用交替的值合并两个数组 [英] Merge two arrays with alternating Values

问题描述

我想合并2个不同长度的数组：

  let array2 = [a，b ，c，d]; 
让array2 = [1，2]; 
 $ b让结果= [a，1，b，2，c，d] 
  

最好的方法是做什么？

编辑：我期望得到的结果是 [a，1，b，2，你可以迭代数组和构建的最小长度，这样就可以实现数组和构建的最小长度data-lang =jsdata-hide =falsedata-console = truedata-babel =false>

var array1 = [ a，b，c，d]，array2 = [1,2]，result = []，i，l = Math.min（array1.length，array2.length）;对于（i = 0; i <1; i ++）{result.push（array1 [i]，array2 [i]）;} result.push（... array1.slice（l），... array2.slice （l））; console.log（result）;

对于任意数量的具有移位算法的数组，然后展平。



var array1 = [a，b，c，d]，array2 = [1,2]，result = [array1，array2] .reduce（（r，a）=>（a.forEach （（a，i）=>（r [i] = r [i] || []）。的concat（b））; console.log（result）;

i would like to merge 2 arrays with a different length:

let array2 = ["a", "b", "c", "d"];
let array2 = [1, 2];

let outcome = ["a",1 ,"b", 2, "c", "d"] 

Whats the best way to do that?

Edit: The outcome I would expect is ["a", 1 ,"b", 2, "c", "d"]

解决方案

You could iterate the min length of both array and build alternate elements and at the end push the rest.

var array1 = ["a", "b", "c", "d"],
    array2 = [1, 2],
    result = [],
    i, l = Math.min(array1.length, array2.length);
    
for (i = 0; i < l; i++) {
    result.push(array1[i], array2[i]);
}
result.push(...array1.slice(l), ...array2.slice(l));

console.log(result);

Solution for an arbitrary count of arrays with a transposing algorithm and later flattening.

var array1 = ["a", "b", "c", "d"],
    array2 = [1, 2],
    result = [array1, array2]
        .reduce((r, a) => (a.forEach((a, i) => (r[i] = r[i] || []).push(a)), r), [])
        .reduce((a, b) => a.concat(b));
    
console.log(result);

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