如何设置延迟的Andr​​oid的onClick功能 [英] How to set delay in Android onClick function

问题描述

） 我是在创造一个记忆游戏的过程。我的问题是，每当我点击第二次，我甚至不能看到切换按钮。需要明确的是 - 先点击切换切换按钮，这样我就可以看到它持有，第二次点击不同的切换按钮被suposed切换它的数量，显示我的号码，然后进行任何设置一个分数+1，如果数字是同样的，或者逆向他们回来，如果他们是不同的。

) I'm in a process of creating a memory game. My problem is that whenever i click for the second time, i can't even see toggled button. To be clear - first click toggles the togglebutton, so i can see the number it holds, the second click on a different togglebutton is suposed to toggle it, show me the number and then proceed to either set a score +1 if numbers are the same, or reverse them back again if they're different.

下面是我为我的onClick功能使用code，我一直在思考把某种睡眠或延迟功能的somwhere在第二个假如块 - （如果（klikniecia == 2））

Below is the code that i use as my onClick function, i've been thinking about putting some kind of sleep or delay function somwhere in the second "if block" - (if(klikniecia ==2)).

有关此主题的任何帮助将是AP preciated。

Any help on this topic would be appreciated.

public void onClick(View view) {
for (int i = 0; i < karta.length; i++){
    if (view == karta[i]){
        karta[i].setEnabled(false);
        klikniecia++;
        if (klikniecia == 1){
            kartaID[0]=i;
            kartaWartosc[0]=listaKart.get(i);

        }
        if (klikniecia == 2){
            kartaID[1]=i;
            kartaWartosc[1]=listaKart.get(i);

            //i think, about setting a delay here, so i can see both of the cards, regardles if the're the same or not before reverting them.

            if (czyPara()){
                karta[kartaID[0]].setEnabled(false);
                karta[kartaID[1]].setEnabled(false);
                klikniecia=0;
            }
            else{

                karta[kartaID[0]].setEnabled(true);
                karta[kartaID[0]].toggle();
                karta[kartaID[1]].setEnabled(true);
                karta[kartaID[1]].toggle();
                klikniecia=0;

            }
        }

    }

}

}

推荐答案

而不是睡在onclick，你可以发布延迟的消息处理程序（具有相关的可运行），并将它更新UI。显然，这符合到你的应用程序的设计，使其工作，但基本的思路是这样的：

Instead of sleeping in the onclick, you could post a delayed message to a handler (with associated runnable) and have it update the UI. Obviously fit this into the design of your app and make it work, but the basic idea is this:

//Here's a runnable/handler combo
private Runnable mMyRunnable = new Runnable()
{
    @Override
    public void run()
    {
       //Change state here
    }
 };

再从你的onClick发布延迟的消息处理程序，指定可运行执行。

Then from onClick you post a delayed message to a handler, specifying that runnable to be executed.

Handler myHandler = new Handler();
myHandler.postDelayed(mMyRunnable, 1000);//Message will be delivered in 1 second.

根据你的游戏是多么的复杂，这可能不是正是你想要的，但它应该给你一个开始。

Depending on how complicated your game is, this might not be exactly what you want, but it should give you a start.

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