如何初始化wchar_t变量? [英] How to initialize a wchar_t variable?
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问题描述
我正在读这本书: C:In a Nutshell ,并且在阅读关于宽字符的字符集部分之后,我编写了这个程序: p>
I am reading the book: C: In a Nutshell, and after reading the section Character Sets, which talks about wide characters, I wrote this program:
#include <stdio.h>
#include <stddef.h>
#include <wchar.h>
int main() {
wchar_t wc = '\x3b1';
wprintf(L"%lc\n", wc);
return 0;
}
然后我使用gcc编译它,但是gcc给了我这个警告:
$ b
I then compiled it using gcc, but gcc gave me this warning:
main.c:7:15:警告:十六进制转义序列超出范围[默认情况下启用]
main.c:7:15: warning: hex escape sequence out of range [enabled by default]
该程序不会输出字符α(其Unicode编码为U + 03B1),这正是我想要的。
And the program does not output the character α (whose unicode is U+03B1), which is what I wanted it to do.
如何更改程序打印字符α?
How do I change the program to print the character α?
推荐答案
这适用于我
#include <stdio.h>
#include <stddef.h>
#include <wchar.h>
#include <locale.h>
int main(void) {
wchar_t wc = L'\x3b1';
setlocale(LC_ALL, "en_US.UTF-8");
wprintf(L"%lc\n", wc);
return 0;
}
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