如何从泛型类或方法的成员中获取T的类型? [英] How to get the type of T from a member of a generic class or method?
问题描述
public class Foo< T>假设我在类或方法中有一个通用成员,
{
public List< T>酒吧{get;组; }
$ b $ public void Baz()
{
//获取类型T
}
}
当我实例化类时, T
变成 MyTypeObject1
,因此该类具有通用列表属性: List< MyTypeObject1>
。这同样适用于非泛型类中的泛型方法:
public class Foo
{
public void Bar< T>()
{
var baz = new List< T>();
//获得类型T
}
}
我想知道,我的类的列表包含什么类型的对象。因此,名为 Bar
或本地变量 baz
的列表属性包含 T
?
我不能做 Bar [0] .GetType()
,因为列表可能包含零个元素。我如何做到这一点?
如果我理解正确,您的列表与容器类本身具有相同的类型参数。如果是这种情况,那么:
类型typeParameterType = typeof(T);
如果您处于 object
作为类型参数,请参阅 Marc的答案。
Let say I have a generic member in a class or method, so:
public class Foo<T>
{
public List<T> Bar { get; set; }
public void Baz()
{
// get type of T
}
}
When I instantiate the class, the T
becomes MyTypeObject1
, so the class has a generic list property: List<MyTypeObject1>
. The same applies to a generic method in a non-generic class:
public class Foo
{
public void Bar<T>()
{
var baz = new List<T>();
// get type of T
}
}
I would like to know, what type of objects the list of my class contains. So the list property called Bar
or the local variable baz
, contains what type of T
?
I cannot do Bar[0].GetType()
, because the list might contain zero elements. How can I do it?
If I understand correctly, your list has the same type parameter as the container class itself. If this is the case, then:
Type typeParameterType = typeof(T);
If you are in the lucky situation of having object
as a type parameter, see Marc's answer.
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